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4 years ago

Show the solution of the equation 2 1/7 + 3/7 (3x-5)=-4

Mathematics

2 answers:

vekshin14 years ago

5 0

2 1/7 + 3/7 (3x-5)= - 4

2 1/7 + (9/7)x - 15/7 = - 4

15/7 + (9/7)x - 15/7 = - 4

(9/7)x = - 4

x = - 4 * 7/9 = - 28/9 = - 3 1/9

Answer is - 28/9 or - 3 1/9.

Cerrena [4.2K]4 years ago

3 0

I think so. Hope this help you!!

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The Hyperbolic Sine (sinh(x)) and Hyperbolic Cosine (cosh(x)) functions are defined as such: sin h(x) = e^x - e^-x/2 cosh(x) = e

labwork [276]

Answer:

y-incercepts:

sinh(x):0, cosh(x)=1

Limits:

positive infinity: sinh(x): infinity, cosh(x): infinity

negative infinity: sinh(x): - infinity, cosh(x): infinity

Step-by-step explanation:

We are given that

$\sinh(x)=\frac{e^{x}-e^{-x}}{2}$

$\cosh(x)=\frac{e^{x}+e^{-x}}{2}$

To find out the y-incerpt of a function, we just need to replace x by 0. Recall that $e^{0}=1$ . Then,

$\sinh(0) = \frac{1-1}{2}=0$

$\cosh(0) = \frac{1+1}{2}=1$

For the end behavior, recall the following:

$\lim_{x\to \infty}e^{x} = \infty, \lim_{x\to \infty}e^{-x} = 0$

$\lim_{x\to -\infty}e^{x} = 0, \lim_{x\to -\infty}e^{-x} = \infty$

Using the properties of limits, we have that

$\lim_{x\to \infty} \sinh(x) =\frac{1}{2}(\lim_{x\to \infty}e^{x}-\lim_{x\to \infty}e^{-x})=(\infty -0) = \infty$

$\lim_{x\to \infty} \cosh(x) =\frac{1}{2}(\lim_{x\to \infty}e^{x}+\lim_{x\to \infty}e^{-x}) =(\infty -0)= \infty$

$\lim_{x\to -\infty} \sinh(x) =\frac{1}{2}(\lim_{x\to -\infty}e^{x}-\lim_{x\to -\infty}e^{-x}) = (0-\infty)=-\infty$

$\lim_{x\to -\infty} \cosh(x) =\frac{1}{2}(\lim_{x\to -\infty}e^{x}+\lim_{x\to -\infty}e^{-x}) =(0+\infty)= \infty$

8 0

3 years ago

On the dietitians beverage tray are 16 filled six ounce glasses. Four glasses contain prune juice and two glasses contain apple

zubka84 [21]

Answer:

$\frac{5}{8}$

Step-by-step explanation:

Given:

Total number of glasses = 16

Number of glasses containing prune juice = 4

Number of glasses containing apple juice = 2

To find: fractional part of the glasses that contain beverages ( perhaps, H2O) other than prune juice and apple juice

Solution:

A fraction refers to the parts of a whole. In a fraction, a top number is the numerator, and a bottom number is the denominator.

Number of glasses that contain beverages ( perhaps, H2O) other than prune juice and apple juice = 16 - 4 - 2 = 10

Total number of glasses = 16

So,

Fractional part of the glasses that contain beverages ( perhaps, H2O) other than prune juice and apple juice = $\frac{10}{16}=\frac{5}{8}$

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3 years ago

A woman obtained a 2-year loan to cover the costs of a vacation. She was surprised to find that the simple annual interest rate

aleksley [76]

Answer:

$2500

Step-by-step explanation:

The amount of simple interest is computed using the formula ...

I = Prt

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The original amount of the loan was $2500.

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3 years ago

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In which quadrant does the terminal side of 225° angle in standard position lie

Arisa [49]

Answer:

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Step-by-step explanation:

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3 years ago

Find the value of the variable y, where the sum of the fraction 2/y-3 and 6/y+3 is equal to the quotient.

NISA [10]

Answer:

Here we need to solve:

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The sum of the fractions is equal to the quotient between the fractions.

Notice that the two values:

y = 3

y = -3

make the denominator equal to zero, so those values are restricted.

We can simplify the right side to get:

$\frac{2}{y - 3} + \frac{6}{y + 3 } = \frac{\frac{2}{y-3}}{\frac{6}{y + 3} } = \frac{2*(y + 3)}{6*(y - 3)} = 3*\frac{y + 3}{y - 3}$

Now we can multiply both sides by (y - 3)

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Now we can multiply both sides by (y + 3)

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First, let's see the determinant of that quadratic equation:

$D = (-2)^2 - 4*3*45 = -536$

We can see that it is negative, thus, there are no real solutions of the equation.

Thus, there is no value of y such that the origina equation is true,

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3 years ago