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Otrada [13]
3 years ago
11

Determine whether the underlined numerical value is a parameter or a statistic. Explain your reasoning The average grade on the

midterm exam in a certain math class of 50 students was an 88. Choose the correct answer below. O
A. Statistic, because the data set of all 50 midterm exams in the math class is a sample
B. Parameter, because the data set of a sample of math exams is a population.
C. Parameter, because the data set of a sample of math exams is a sample.
D. Statistic, because the data set of a sample of math exams is a population
E. Parameter, because the data set of all 50 midterm exams in the math class is a sample.
F Parameter, because the data set of all 50 midterm exams in the math class is a population
G. Statistic, because the data set of a sample of math exams is a sample
H. Statistic, because the data set of all 50 midterm exams in the math class is a population.
Mathematics
1 answer:
Nat2105 [25]3 years ago
3 0

Answer:

The correct option is F.

Step-by-step explanation:

A parameter is a single numerical value describing a certain characteristic of the entire population. It is computed using the population values. For example, population mean, population variance, etc.

A statistic is also a numerical value that defines certain characteristic of a sample. It is computed using the sample values. For example, sample mean, sample variance, etc.

Here the mean score for all the 50 students in the midterm Math exam is computed as 88.

This mean value is a parameter because it is computed using the entire population of 50 students in the math class,i.e. all the population values were included in the calculation of mean 88.

Thus, the correct option is F.

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Hello from MrBillDoesMath!

Answer:

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Discussion:

The pattern  1,8,27, 64... is immediately recognizable as the the cube of the positive integers. But this question has a minus sign appearing before  each entry, suggesting we try this:


 - 1  =  (-1)^3

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That's what the problem statement asked for . The answer is equivalently

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