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alexgriva [62]
4 years ago
7

Please help, I don't know how to do this.

Mathematics
1 answer:
Zielflug [23.3K]4 years ago
4 0

Answer:

3x^2 +4x-4

Step-by-step explanation:

We know the zeros are  -2 and 2/3

Using the zero product property

(x- -2) (x -2/3) = 0

(x+2) (x-2/3) = 0

We want to write the function, so we need to FOIL

first x*x = x^2

outer: -2/3x

inner: 2x

last: -4/3

Add together

x^2 -2/3x +2x -4/3 =0

x^2 -2/3x+6/3x -4/3 =0

x^2 +4/3x - 4/3 =0

We can multiply by any constant and it will still give us the same zeros

I will multiply by 3 to get rid of the fractions

3(x^2 +4/3x - 4/3) =0*3

3x^2 +4x-4 = 0

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Answer:

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Step-by-step explanation:

The following options are missing:

<em>1)x=-4π/3 </em>

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<em />

The trigonometric function tan(x) has asymptotes at x = π/2 radian and x = -π/2 radian. Therefore, tan(3/4x) would have asymptotes at:

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