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goldenfox [79]
3 years ago
10

Which of the following statements is true?

Mathematics
1 answer:
julia-pushkina [17]3 years ago
5 0
A) A triangle can have two congruent angles.
It's called an Isosceles Triangle
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Add and simplify 9/16+1/2 =
Ad libitum [116K]
Sorry for the bad handwriting.

3 0
3 years ago
Jill has 12 books. She thinks that if she gives away 4 books, she will have 8 books left. Which addition sentence can she use to
laila [671]

Answer:

8+4

Step-by-step explanation:

8 0
2 years ago
3. Try It #3 Write the point-slope form of an equation of a line with a slope of -2 that passes through the point (-2,2). Then r
vova2212 [387]

Answer:

Point-slope form of equation given as $y-2=-2(x+2)$.

Slope-intercept form of equation is given as $y=-2 x-2$.

Step-by-step explanation:

In the question, it is given that the slope of a line is -2 and it passes from (-2,2).

It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.

To do so, first find the values which are given in the question and put it in the formula of point-slope form. Simplify the equation to rewrite as slope-intercept form.

Step 1 of 2

Passing point of the line is (-2,2).

Hence, $x_{1}=-2$ and

$$y_{1}=2 \text {. }$$

Also, the slope of the line is -2.

Hence, m=-2

Substitute the above values in point-slope form of equation given by $y-y_{1}=m\left(x-x_{1}\right)$

$$\begin{aligned}&y-y_{1}=m\left(x-x_{1}\right) \\&y-2=-2(x-(-2) \\&y-2=-2(x+2)\end{aligned}$$

Hence, point-slope form of equation given as y-2=-2(x+2).

Step 2 of 2

Solve y-2=-2(x+2) to write it as slope-intercept form given by y=mx+c.

$$\begin{aligned}&y-2=-2(x+2) \\&y-2=-2 x-4 \\&y=-2 x-4+2 \\&y=-2 x-2\end{aligned}$$

Hence, slope-intercept form of equation is given as y=-2x-2.

7 0
2 years ago
Fill in the blanks to rewrite the following statement with variables: Given any positive real number, there is a positive real n
sveticcg [70]

Answer:

a) there is s such that <u>r>s</u> and s is <u>positive</u>

b) For any <u>r>0</u> , <u>there exists s>0</u> such that s<r

Step-by-step explanation:

a) We are given a positive real number r. We need to wite that there is a positive real number that is smaller. Call that number s. Then r>s (this is equivalent to s<r, s is smaller than r) and s is positive (or s>0 if you prefer). We fill in the blanks using the bold words.

b) The last part claims that s<r, that is, s is smaller than r. We know that this must happen for all posirive real numbers r, that is, for any r>0, there is some positive s such that s<r. In other words, there exists s>0 such that s<r.

3 0
3 years ago
Will mark as brainliest (must show work)
Sever21 [200]

Answer:

46

Step-by-step explanation:

With those problems if you are not given a picture is good we draw one.

Because an angle bisector forms 2 congruent angles and because is given that < XVY ≅ < YVW  then

m < XVY = m < YVW

      2x+7 = x+15 , subtract x and 7 from both sides to isolate the like terms

      2x-x = 15-7, combine like terms

           x = 8

From the picture and the given we see that

m < XVW = m < XVY + m < YVW

m < XVW = 2x+7 + x+15 , combine like terms

m < XVW = 3x + 22, substitute x for 8

m < XVW = 3*8 + 22

m < XVW = 46

Check our work:

m < XVY =  2x+7  = 2*8 +7 = 16 +7 = 23

m < YVW =  x+15 = 8 +15 = 23

m < XVW = m < XVY + m < YVW = 23+23 =46

3 0
2 years ago
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