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Keith_Richards [23]
4 years ago
15

Consider various ways of ordering the letters in the word TENNESSEE. TENENESES, EESSENNET, TNNEESSEE, and so on. (a) How many di

stinguishable orderings are there
Mathematics
1 answer:
scoundrel [369]4 years ago
5 0

Answer:

3780.  

Step-by-step explanation:

To solve this we will start by just considering the number of ways to arrange 9 objects. We can do this in  9!  ways.

However since we have 3 reoccurring letters in Tennessee namely n,s and e we need to remove the times these form the same arrangement. Let me give an example to show what this means. Lets say we have the arrangement:

ennetssee

Now what happens if we exchange the places of the letters n for example? Of course we get the same arrangement of letters. We don’t want to count these as 2 different arrangements since for our interests they are the same. We therefore divide  9!  by the number of times this type of double counting occurs.

Since the word has the letter n occurring twice we will start by diving by  2! .

The letter s occurs 2 times as well so we will have to divide by  2!  again.

Finally the letter e occurs 4 times and so we will have to divide by  4!  here.

Now we get the following result:

9/(2 x 2 x 4)=3780.  

So in conclusion there are 3780 different ways to arrange the letters in Tennessee.

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We have been given that a retailer buys cases of 24 shirts for $30/case and then resells them in packs of 5 for $8/pack.

Further, we know that retailer sold all the shirts he purchased and profited $84 on the sale.

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Now, let us assume that the retailer bought 120x shirts. Therefore total profit will be:

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We can set this equal to the given profit to figure out the value of x first.

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