All categories

3 years ago

Can someone help me with number one please?

Mathematics

2 answers:

zhenek [66]3 years ago

7 0

Yes, x equals 4!
*work if needed*

ludmilkaskok [199]3 years ago

3 0

6x+5=29
29-5= 24
6x=24
24/6=4
x=4

You might be interested in

if $168.00 is the profit on a job, and this represents 8%of the contract price,what is the contract price?

Galina-37 [17]

We are told that $168.00 represents 8% of the contract price; therefore,we know that

original price *( 8/100) = $168.00

Now, writing out "original price" is a bit space-consuming; therefore, we will just rename it and say

original price = OP

Then, our equation above can be written as

$OP\times\frac{8}{100}=168$

We solve for OP (original price) by multiplying both sides by 100 and then dividing by 8. This gives us

$OP=\frac{100}{8}\times168$ $\textcolor{#FF7968}{\therefore OP=2100}\text{\textcolor{#FF7968}{.}}$

Hence, the original contract price is $2100.

6 0

1 year ago

2−2n=3n+17 what IS THE answer help

Stolb23 [73]

First, let's identify the like terms.
2 and 17
2n and 3n

Next, you would need to combine them. Ex: Add 2n to both sides, and subtract 17 from both sides.
2 - 2n = 3n + 17
2 = 5n + 17
-15 = 5n

Now, all you would need to do is isolate the n. To do this, you would divide both sides by 5.
-15 = 5n
-3 = n

n = -3

The solution would be -3.

I hope this helps!

6 0

3 years ago

Read 2 more answers

SOLVE THIS QUESTION

ASHA 777 [7]

447/250

is the answer to the question

4 0

3 years ago

Read 2 more answers

You are at the bottom of a mountain where the temperature is 74°F. The top of the mountain is 5500 feet above you. What is the t

KIM [24]

For every 1,000 feet you go up in elevation, the temperature decreases by about 3.3°F

Given:

Temperature at the bottom of the mountain is 74°F

The top of the mountain is 5500 feet above you

Change (reduction) in temperature is 3.3 X 5500 / 1000

= 18.15°F

Temperature at the top of the mountain is 74°F – 18.15°F

= 55.85°F

6 0

3 years ago

Assume z = x + iy, then find a complex number z satisfying the given equation. d. 2z8 – 2z4 + 1 = 0

kodGreya [7K]

Answer: complex equations has n number of solutions, been n the equation degree. In this case:

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i11,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i101,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i191,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i281,25°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i78,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i168,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i258,75°}$

$Z=\frac{\sqrt[8]{2} }{\sqrt[4]{2}} e^{i348,75°}$

Step-by-step explanation:

I start with a variable substitution:

$Z^{4} = X$

Then:

$2X^{2}-2X+1=0$

Solving the quadratic equation:

$X_{1} =\frac{2+\sqrt{4-4*2*1} }{2*2} \\X_{2} =\frac{2-\sqrt{4-4*2*1} }{2*2}$

$X=\left \{ {{0,5+0,5i} \atop {0,5-0,5i}} \right.$

Replacing for the original variable:

$Z=\sqrt[4]{0,5+0,5i}$

or $Z=\sqrt[4]{0,5-0,5i}$

Remembering that complex numbers can be written as:

$Z=a+ib=|Z|e^{ic}$

Using this:

$Z=\left \{ {{{\frac{\sqrt{2}}{2} e^{i45°} } \atop {{\frac{\sqrt{2}}{2} e^{i-45°} }} \right.$

Solving for the modulus and the angle:

$Z=\left \{ {{\sqrt[4]{\frac{\sqrt{2}}{2} e^{i45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i45}} } \atop {\sqrt[4]{\frac{\sqrt{2}}{2} e^{i-45}} = \sqrt[4]{\frac{\sqrt{2}}{2} } \sqrt[4]{e^{i-45}} }} \right.$

The possible angle respond to:

$RAng_{12...n} =\frac{Ang +360*(i-1)}{n}$

Been "RAng" the resultant angle, "Ang" the original angle, "n" the degree of the root and "i" a value between 1 and "n"

In this case n=4 with 2 different angles: Ang = 45º and Ang = 315º

Obtaining 8 different angles, therefore 8 different solutions.

3 0

3 years ago