Question

Find the width of a rectangle 25 feet and the perimeter is 80​

Answer 1

The width of rectangle = 15 feet .

Step-by-step explanation:

Given =

• Perimeter of rectangle = 80
• Length of rectangle = 25 feet

To Find =

• width or Breadth of rectangle.

As we know ,

Perimeter of rectangle = 2× (L + B )

• where L is Length and B is width or Breadth.

Filling values in the formula :-

=> 80 = 2 ( 25 + B )

• we don't know the value of ' B' so we put ' B' as it is .

=> 80/2 = 25 + B

=> 40 = 25 + B

• when we combine like terms one side signs will be changed from + to - .

=> B = 40 - 25

=> B = 15 feet .

________________

Properties of rectangle :

1. It is a quadrilateral
2. each angle is 90° .
3. sum of angles is 360°
4. Opposite sides are equal.
5. Diagonals bisect each other.

Perimeter of rectangle = 2× L+B

Area = L×B .

Answer 2

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

• Given - a rectangle with length 25 feet and perimeter 80 feet

• To calculate - width of the rectangle

We know that ,

$\bold{Perimeter \: of \: rectangle = 2(l + b)}$

where b = width / breadth of rectangle

‎ ‎ ‎

substituting the values in the formula stated above ,

$\bold{80 = 2(25 + b)} \\ \\\bold{ \implies \: 25 + b = \cancel \frac{80}{2} } \\ \\ \bold{\implies \: 25 + b = 40 }\\ \\ \bold{\implies \: b = 40 - 25 }\\ \\\bold{ \implies \: b = 15 \: feet}$

hope helpful ~