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2 years ago

Find the width of a rectangle 25 feet and the perimeter is 80

Mathematics

2 answers:

Thepotemich [5.8K]2 years ago

5 0

The width of rectangle = 15 feet .

Step-by-step explanation:

<h2>Given = </h2>

Perimeter of rectangle = 80
Length of rectangle = 25 feet

width or Breadth of rectangle.

As we know ,

Perimeter of rectangle = 2× (L + B )

where L is Length and B is width or Breadth.

Filling values in the formula :-

=> 80 = 2 ( 25 + B )

we don't know the value of ' B' so we put ' B' as it is .

=> 80/2 = 25 + B

=> 40 = 25 + B

when we combine like terms one side signs will be changed from + to - .

=> B = 40 - 25

=> B = 15 feet .

Properties of rectangle :

It is a quadrilateral
each angle is 90° .
sum of angles is 360°
Opposite sides are equal.
Diagonals bisect each other.

Perimeter of rectangle = 2× L+B

Area = L×B .

lukranit [14]2 years ago

3 0

$\huge\underline{\red{A}\blue{n}\pink{s}\purple{w}\orange{e}\green{r} -}$

Given - a rectangle with length 25 feet and perimeter 80 feet

To calculate - width of the rectangle

We know that ,

$\bold{Perimeter \: of \: rectangle = 2(l + b)} \\$

where b = width / breadth of rectangle

‎ ‎ ‎

substituting the values in the formula stated above ,

$\bold{80 = 2(25 + b)} \\ \\\bold{ \implies \: 25 + b = \cancel \frac{80}{2} } \\ \\ \bold{\implies \: 25 + b = 40 }\\ \\ \bold{\implies \: b = 40 - 25 }\\ \\\bold{ \implies \: b = 15 \: feet}$

hope helpful ~

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Find the width of a rectangle 25 feet and the perimeter is 80​

Find the width of a rectangle 25 feet and the perimeter is 80