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Lelu [443]
4 years ago
12

- 1) Which expression is equivalent to-4-9? 4 - 9 -4+ (-9) - 4+9 4 + 9

Mathematics
2 answers:
Effectus [21]4 years ago
8 0

-4-9 =-13

4-9=-5

-4+(-9): +positive sign and -negative sign=- negative sign

-4-9=-13

-4+9=5

4+9=13

Answer:

-4+ (-9)

Juli2301 [7.4K]4 years ago
5 0

Answer:

-4+(-9)

Step-by-step explanation:

-4-9=-13 and-4+(-9)=-13

which means they're equivalent to each other

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Find the slope of the line that contains the points (3, -6) and (9, 2).
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4 years ago
A group of 4 friends like to bowl together, and each friend keeps track of his all-time highest score in a single game. Their hi
3241004551 [841]

Answer:

The mean will increase, and the median will stay the same.

Step-by-step explanation:

We know that the mean of scores is the average value of the scores of  the score obtained by 4 friends.

i.e. it is the ratio of sum of scores of 4 friends to the total number of person i.e. 4.

Hence, if the score of any of the person will increase then the mean will also increase

( Since, the denominator remains the same and the numerator is increasing so , the resultant value will increase )

Also, we know that the median of the score lie between the data set, i.e. the change in the score of the last score won't affect the median :

Since, here we have  4 data points and the median lie between the 2nd and 3rd data point so change in the 4th data point won't affect the median.

Hence, increasing Adam's high score affect the mean and median as:

Mean will increase and Median remains the same.

5 0
4 years ago
We wish to construct a 90% confidence interval on the mean of a population known to be normally distributed based on a sample of
sergiy2304 [10]

Answer:

Margin of error = 0.773

Step-by-step explanation:

We are given the following information in the question.

Sample size, n = 20

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Sample standard deviation = 2

90% Confidence interval

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.10} = \pm 1.729  

Margin of error:

t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

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1.729(\frac{2}{\sqrt{20}} ) = 0.773  

7 0
4 years ago
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