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lilavasa [31]
3 years ago
10

A group of 4 friends like to bowl together, and each friend keeps track of his all-time highest score in a single game. Their hi

gh scores are all between 180 and 220, except for Adam, whose high score is 250.Adam then bowls a great game and has a new high score of 290 How will increasing Adam's high score affect the mean and median?
Mathematics
1 answer:
3241004551 [841]3 years ago
5 0

Answer:

The mean will increase, and the median will stay the same.

Step-by-step explanation:

We know that the mean of scores is the average value of the scores of  the score obtained by 4 friends.

i.e. it is the ratio of sum of scores of 4 friends to the total number of person i.e. 4.

Hence, if the score of any of the person will increase then the mean will also increase

( Since, the denominator remains the same and the numerator is increasing so , the resultant value will increase )

Also, we know that the median of the score lie between the data set, i.e. the change in the score of the last score won't affect the median :

Since, here we have  4 data points and the median lie between the 2nd and 3rd data point so change in the 4th data point won't affect the median.

Hence, increasing Adam's high score affect the mean and median as:

Mean will increase and Median remains the same.

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Take the augmented matrix,

\left[\begin{array}{ccc|c}2&1&-3&-20\\1&2&1&-3\\1&-1&5&19\end{array}\right]

Swap the row 1 and row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\2&1&-3&-20\\1&-1&5&19\end{array}\right]

Add -2(row 1) to row 2, and -1(row 1) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&-3&4&22\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&9&36\end{array}\right]

Multiply through row 3 by 1/9:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&-5&-14\\0&0&1&4\end{array}\right]

Add 5(row 3) to row 2:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&-3&0&6\\0&0&1&4\end{array}\right]

Multiply through row 2 by -1/3:

\left[\begin{array}{ccc|c}1&2&1&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

Add -2(row 2) and -1(row 3) to row 1:

\left[\begin{array}{ccc|c}1&0&0&-3\\0&1&0&-2\\0&0&1&4\end{array}\right]

So we have \boxed{x=-3,y=-2,z=4}.

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3 years ago
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