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4 years ago

Simpl equestoin please canserr for me.

Mathematics

2 answers:

Lerok [7]4 years ago

5 0

So, this is how we do it O w Ox = −1;y = 3x+1Step: Solve x = −1 for x:Step: Substitute −1 for x in y = 3x+1:y = 3x+1y = (3)(−1)+1y = −2(Simplify both sides of the equation)Answer:x=−1 and y=−2
Hope I helped! :3

zimovet [89]4 years ago

4 0

The answer is: [B]: (-1, -2) .
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Please help as soon as possible PLEASE

pashok25 [27]

Area of the entire rectangle $=x^2+10x+24$

Solution:

Area of the blue box = length × width

$=x\times x$

Area of the blue box $=x^2$

Area of the pink box = length × width

$=4\times x$

Area of the pink box $=4x$

Area of the green box = length × width

$=6\times x$

Area of the green box $=6x$

Area of the orange box = length × width

$=6\times 4$

Area of the orange box = 24

Total area of the rectangle $=x^2+4x+6x+24$

$=x^2+10x+24$

Area of the entire rectangle $=x^2+10x+24$

4 0

3 years ago

Can someone answer this plz (-2z^2-14)-(-12z^2)

Orlov [11]

Answer:

$\large\boxed{(-2z^2-14)-(-12z^2)=10z^2-14}$

Step-by-step explanation:

$(-2z^2-14)-(-12z^2)=-2z^2-14+12z^2\qquad\text{combine like terms}\\\\=(-2z^2+12z^2)-14=10z^2-14$

8 0

4 years ago

The length of a rectangle is 4 cm longer than the width, The perimeter is 80 cm. Find the length and the width. Substition Metho

MrRa [10]

Answer: Length = l

Width = w

2l + 2w = 80cm

l+w = 40cm

l = w+4

w+4 + w = 40cm

2w + 4 = 40cm

2w = 36cm

w = 18cm

l = 22cm

jd3sp4o0

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Is this correct? If not, please tell me the correct answer!!!

White raven [17]

Answer:

That is correct

Step-by-step explanation:

180° rotation about origin just means that you have to flip the pre-existing image across the x-axis

Good job!

3 0

4 years ago

A Norman window is a window with a semi-circle on top of regular rectangular window. (See the picture.) What should be the dimen

Vikki [24]

Answer:

bottom side (a) = 3.36 ft

lateral side (b) = 4.68 ft

Step-by-step explanation:

We have to maximize the area of the window, subject to a constraint in the perimeter of the window.

If we defined a as the bottom side, and b as the lateral side, we have the area defined as:

$A=A_r+A_c/2=a\cdot b+\dfrac{\pi r^2}{2}=ab+\dfrac{\pi}{2}\left (\dfrac{a}{2}\right)^2=ab+\dfrac{\pi a^2}{8}$

The restriction is that the perimeter have to be 12 ft at most:

$P=(a+2b)+\dfrac{\pi a}{2}=2b+a+(\dfrac{\pi}{2}) a=2b+(1+\dfrac{\pi}{2})a=12$

We can express b in function of a as:

$2b+(1+\dfrac{\pi}{2})a=12\\\\\\2b=12-(1+\dfrac{\pi}{2})a\\\\\\b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a$

Then, the area become:

$A=ab+\dfrac{\pi a^2}{8}=a(6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a)+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a^2+\dfrac{\pi a^2}{8}\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{4}-\dfrac{\pi}{8}\right)a^2\\\\\\A=6a-\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right)a^2$

To maximize the area, we derive and equal to zero:

$\dfrac{dA}{da}=6-2\left(\dfrac{1}{2}+\dfrac{\pi}{8}\right )a=0\\\\\\6-(1-\pi/4)a=0\\\\a=\dfrac{6}{(1+\pi/4)}\approx6/1.78\approx 3.36$

Then, b is:

$b=6-\left(\dfrac{1}{2}+\dfrac{\pi}{4}\right)a\\\\\\b=6-0.393*3.36=6-1.32\\\\b=4.68$

3 0

4 years ago