A skydiver jumps from an airplane at an altitude of 2,500 ft. He falls under the force of gravity until he opens his parachute a
t an altitude of 1,000 ft. Approximately how long does the jumper fall before he opens his chute?
1 answer:
I think the answer is 2.5
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Answer:
4-4x=12+16x
−4x+4=16x+12
−4+4−4=16+12−4
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-4x-16x=16x+8-16x
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x= -2/5
Answer:
291.666666667
Step-by-step explanation:
Rounds to 291.7
