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3 years ago

7

Zelda bought a blouse and a sweater for a total price of $79. The price of the sweater was $4 more than twice the price of the b

louse. What was the price of the blouse?

1 answer:

Bogdan [553]3 years ago

6 0

A correct possibility could be $37.50 because 37.50 x 2 + 4 = 79

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A = 1011 + 337 + 337/2 +1011/10 + 337/5 + ... + 1/2021

egoroff_w [7]

The sum of the given series can be found by simplification of the number

of terms in the series.

A is approximately <u>2020.022</u>

Reasons:

The given sequence is presented as follows;

A = 1011 + 337 + 337/2 + 1011/10 + 337/5 + ... + 1/2021

Therefore;

$\displaystyle A = \mathbf{1011 + \frac{1011}{3} + \frac{1011}{6} + \frac{1011}{10} + \frac{1011}{15} + ...+\frac{1}{2021}}$

The n + 1 th term of the sequence, 1, 3, 6, 10, 15, ..., 2021 is given as follows;

$\displaystyle a_{n+1} = \mathbf{\frac{n^2 + 3 \cdot n + 2}{2}}$

Therefore, for the last term we have;

$\displaystyle 2043231= \frac{n^2 + 3 \cdot n + 2}{2}$

2 × 2043231 = n² + 3·n + 2

Which gives;

n² + 3·n + 2 - 2 × 2043231 = n² + 3·n - 4086460 = 0

Which gives, the number of terms, n = 2020

$\displaystyle \frac{A}{2} = \mathbf{ 1011 \cdot \left(\frac{1}{2} +\frac{1}{6} + \frac{1}{12}+...+\frac{1}{4086460} \right)}$

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2} +\frac{1}{2} - \frac{1}{3} + \frac{1}{3}- \frac{1}{4} +...+\frac{1}{2021}-\frac{1}{2022} \right)$

Which gives;

$\displaystyle \frac{A}{2} = 1011 \cdot \left(1 - \frac{1}{2022} \right)$

$\displaystyle A = 2 \times 1011 \cdot \left(1 - \frac{1}{2022} \right) = \frac{1032231}{511} \approx \mathbf{2020.022}$

A ≈ <u>2020.022</u>

Learn more about the sum of a series here:

brainly.com/question/190295

8 0

2 years ago

Read 2 more answers

HELP PLEASE GEOMETRY find x and y

dimulka [17.4K]

$3x + 30 + 2x - 20 = 360 \\ 5x + 10 = 360 \\ 5x = 350 \\ x = 70$
$y = \frac{3x + 30 - 2x + 20}{2} = \frac{x + 50}{2} = \frac{120}{2} = 60$

3 0

3 years ago

If tan theta =3, find the value of tan theta + tan (theta+pi) + tan (theta +2pi)

sweet-ann [11.9K]

Answer:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

Step-by-step explanation:

Given

$tan\theta = 3$

Required

Find

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$

Calculate $tan(\theta + \pi) \ and\ tan(\theta+2\pi)$

Using tan rule

$tan(\theta + \pi) = \frac{tan\theta + tan\pi}{1 - tan\theta tan\pi}$

So:

$tan(\theta + \pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + \pi) = \frac{tan\theta}{1 }$

$tan(\theta + \pi) = \tan\theta$

$tan(\theta+2\pi)$

$tan(\theta + 2\pi) = \frac{tan\theta + tan2\pi}{1 - tan\theta tan2\pi}$

$tan(\theta + 2\pi) = \frac{tan\theta + 0}{1 - tan\theta *0}$

$tan(\theta + 2\pi) = \tan\theta$ '

'So:

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi)$ $= tan\theta +tan\theta +tan\theta$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 3+3+3$

$tan\theta + tan(\theta + \pi) + tan(\theta+2\pi) = 9$

4 0

2 years ago

One of the loudest sounds in recent history was that made by the explosion of Krakatoa on August 26-27, 1883. According to barom

liraira [26]

Answer:

150.51 dB

Step-by-step explanation:

Data provided in the question:

decibel level of sound at 161 km distance = 180 dB

d₁ = 161 km

d₂ = 4800 km

I₁ = 180 db

The formula for intensity of sound is given as:

I = $10\log(\frac{I_2}{I_1})$

and the relation between intensity and distance is given as:

I ∝ $\frac{1}{d^2}$

or

Id² = constant

thus,

I₁d₁² = I₂d₂²

or

$\frac{I_2}{I_1}=\frac{d_1}{d_2}$

therefore,

I = $10\log(\frac{d_1}{d_2})^2$

or

I = $10\times2\times\log(\frac{161}{4,800})$

or

I = 20 × (-1.474)

or

I = -29.49

Therefore,

the decibel level on Rodriguez Island, 4,800 km away

= 180 - 29.49

= 150.51 dB

8 0

3 years ago

HELP ASAP please help I’ll mark as a brnlist

Mariana [72]

Answer:

Step-by-step explanation:

perpendicular (P) = 6

base (b) = 8

hypotenuse (h) =?

we know by using Pythagoras theorem,

h = $\sqrt{(p)^{2} + (b)^{2} } \\$

= $\sqrt{(6)^{2} + (8)^{2} } \\$

= 10

5 0

3 years ago