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3 years ago

HELP ASAP please help I’ll mark as a brnlist

Mathematics

1 answer:

Mariana [72]3 years ago

5 0

Answer:

Step-by-step explanation:

perpendicular (P) = 6

base (b) = 8

hypotenuse (h) =?

we know by using Pythagoras theorem,

h = $\sqrt{(p)^{2} + (b)^{2} } \\$

= $\sqrt{(6)^{2} + (8)^{2} } \\$

= 10

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A population of 550 rabbits is increasing by 7.5% each year. In about how many years will the population be over 1000?

Dovator [93]

Answer:

D.) 15 years

Step-by-step explanation:

7.5% of 550 rabbits would be 41.25

if you are increasing till you get over 1,000

it would take 10.9 almost 11 years to get to 1,000

meaning it would be 15 years when your over 1,000 giving you 1,168.75

8 0

3 years ago

At Taylor Street School, 40% of the students bought lunch in the cafeteria today. Of the students who bought lunch in the cafete

leva [86]

Answer:

Probability that she or he bought lunch in the cafeteria and chose pizza as an entree = 12/100 =0.12 = 12%

Explanation:

Let number of students be 100.

At Taylor Street School, 40% of the students bought lunch in the cafeteria today

Number of students bought lunch = 100 x 40/100 = 40

Of the students who bought lunch in the cafeteria today, 30% chose pizza as their entree

Number of students bought pizza = 40 x 30/100 = 12.

Probability of an outcome = Number of favorable outcome/ Total number of outcome

Probability that she or he bought lunch in the cafeteria and chose pizza as an entree = Number of students bought pizza/Total number of students

= 12/100 =0.12 = 12%

Probability that she or he bought lunch in the cafeteria and chose pizza as an entree = 12/100 =0.12 = 12%

4 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago

Log(x+6)-log(x-3)=1<br><br> I need to show work, please show me how

Illusion [34]

Answer:

x = 4.

Step-by-step explanation:

log(x + 6)- log(x - 3) = 1

Using the law log a - log b = log a/b:

log (x + 6)/ (x - 3) = 1

Removing logs:

(x + 6)/ (x - 3) = 10

x+ 6 = 10x - 30

9x = 36

x = 4 (answer).

8 0

3 years ago

Read 2 more answers

Find the times (to the nearest hundredth of a second) that the weight is halfway to its maximum negative position over the inter

hoa [83]

Answer:

0.20 and 0.36

Step-by-step explanation:

y(t) = 2 sin (4π t) + 5 cos (4π t)

We wish to convert this to:

y = A sin(ωt + φ)

We know that ω = 4π. We also know the following:

5 = A sin φ

2 = A cos φ

Divide the first equation by the second equation:

5/2 = tan φ

φ = tan⁻¹(5/2)

Now, square the two equations and add them together.

5² + 2² = (A sin φ)² + (A cos φ)²

29 = A²

A = √29

The equation of the wave is therefore:

y = √29 sin(4π t + tan⁻¹(5/2))

The maximum negative position is -√29. And half of that is -½√29.

-½√29 = √29 sin(4π t + tan⁻¹(5/2))

-½ = sin(4π t + tan⁻¹(5/2))

7π/6 + 2kπ or 11π/6 + 2kπ = 4π t + tan⁻¹(5/2)

7 + 12k or 11 + 12k = 24t + 6 tan⁻¹(5/2) / π

t = (7 + 12k − 6 tan⁻¹(5/2) / π) / 24 or (11 + 12k − 6 tan⁻¹(5/2) / π) / 24

Trying different integer values of k, we find there are two possible values for t between 0 and 0.5, both when k = 0.

t = (7 − 6 tan⁻¹(5/2) / π) / 24 or (11 − 6 tan⁻¹(5/2) / π) / 24

t ≈ 0.20 or 0.36

5 0

3 years ago