Answer:
the 2nd one
Step-by-step explanation:
Answer:
59.16 units
Step-by-step explanation:
Given that,
The length of rectangle, L = 13
The breadth of the rectangle, B = 6
The perimeter of the shaded region = perimeter of rectangle - 2(perimeter of semicircle)
![P=13\times 6-[2\times \dfrac{2\pi r}{2}]\\\\=78-2\pi r\\\\=78-2\times 3.14\times 3\\\\=59.16](https://tex.z-dn.net/?f=P%3D13%5Ctimes%206-%5B2%5Ctimes%20%5Cdfrac%7B2%5Cpi%20r%7D%7B2%7D%5D%5C%5C%5C%5C%3D78-2%5Cpi%20r%5C%5C%5C%5C%3D78-2%5Ctimes%203.14%5Ctimes%203%5C%5C%5C%5C%3D59.16)
So, the perimeter of the shaded region is 59.16 units.
Answer:
hello : sin(θ) = 4/25
Step-by-step explanation:
you know : cos²(θ) + sin²(θ) =1 and : cos(θ) = - 3/5
(-3/5)² + sin²(θ) =1
9/25 + sin²(θ) =1
sin²(θ) =1 -9/25
sin²(θ) = 16/25
sin(θ) = 4/25 or sin(θ) = - 4/25
in quadrant 2 : sin(θ) > 0
so : sin(θ) = 4/25
Answer:

Step-by-step explanation:

Flip the equation:

Subtract 6 from both sides:


Divide both sides by 2:

