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elixir [45]
4 years ago
7

Which graph represents the system 3x + 5y ≤ 9 and 2x + y ≥ 5?

Mathematics
2 answers:
shusha [124]4 years ago
7 1

Answer with Step-by-step explanation:

we are given system of inequalities:

3x + 5y ≤ 9 and

2x + y ≥ 5

We have to determine the graph of the above system

In Second and third graph point (0,6) lies in shaded region

Putting (0,6) in 3x + 5y ≤ 9

3×0+5×6≤9

⇒ 30≤9 which is incorrect

Hence, second and third are not its graph

In fourth graph (0,3) lies in shaded region

Putting (0,3) in 3x + 5y ≤ 9

3×0+5×3≤9

⇒ 15≤9 which is incorrect

Hence, fourth is not its graph

Hence, the only option we are left is graph first

Hence, first graph is the correct representation of 3x + 5y ≤ 9 and

2x + y ≥ 5

Alexandra [31]4 years ago
4 1
Graph A is the correct answer
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Pls answer! I don’t know math @ all
Lana71 [14]

The probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is \frac{5}{12}.

Solution:

Total number of outcomes N(S) = 36

Let A be the sum that is a multiple of 6 and

B be the sum that is a multiple of 4.

Sum that is a multiple of 6 = (1, 5), (2, 4), (3, 3), (4, 2), (5, 1), (6, 6)

N(A) = 6

Sum that is a multiple of 4 = (1, 3), (2, 2), (2, 6), (3, 1), (3, 5),

                                              (4, 4), (5, 3), (6, 2), (6, 6)

N(B) = 9

$P(A)=\frac{N(A)}{N(S)}

$P(A)=\frac{6}{36}=\frac{1}{6}

$P(B)=\frac{N(B)}{N(S)}

$P(B)=\frac{9}{36}=\frac{1}{4}

Probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4:

P(A \cup B)=P(A)+P(B)

$P(A \cup B)=\frac{1}{6} +\frac{1}{4}

               $=\frac{2+3}{12} (Make the denominator same)

               $=\frac{5}{12}

Hence the probability that the outcome is a sum that is a multiple of 6 or a sum that is a multiple of 4 is \frac{5}{12}.

8 0
3 years ago
The mean of the numbers 5, 2x, 4 and 3 is 5 find the value of x<br>​
Fittoniya [83]

Answer:

<em><u>Mean</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>sum</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>outcomes</u></em><em><u>/</u></em><em><u>no</u></em><em><u>.</u></em><em><u> </u></em><em><u>of</u></em><em><u> </u></em><em><u>outcomes</u></em>

<em><u>5</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>(</u></em><em><u>5</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em><em><u>+</u></em><em><u>4</u></em><em><u>+</u></em><em><u>3</u></em><em><u>)</u></em><em><u>/</u></em><em><u>4</u></em>

<em><u>2</u></em><em><u>0</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>1</u></em><em><u>2</u></em><em><u>+</u></em><em><u>2</u></em><em><u>x</u></em>

<em><u>8</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>2</u></em><em><u>x</u></em>

<em><u>8</u></em><em><u>/</u></em><em><u>2</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>x</u></em>

<em><u>4</u></em><em><u> </u></em><em><u>=</u></em><em><u> </u></em><em><u>x</u></em>

<em><u>\\</u></em>

<h2><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em><em><u>_</u></em></h2>

Step-by-step explanation:

<h2>HOPE IT WILL HELP YOU✌✌✌✌✌</h2>
7 0
3 years ago
Read 2 more answers
8 = 6 + a/4 a=___ help
mart [117]

Answer:

<h2>a=8</h2>

Step-by-step explanation:

<h3>6+a/4 = 8</h3><h3>a/4=8-6</h3><h3>a=4×2</h3><h3>a=8</h3>
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An automobile tire loses t milliliters of tread traveling m miles. What is the independent variable?
CaHeK987 [17]
Dependent variable is dependent on the independent variable

m, because the amount of tread lost depends on how many miles you traveled
it's not, the amount of miles depends on how much tread you lost


m is indepdent

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