Answer:
The approximate probability that more than 360 of these people will be against increasing taxes is P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
The right answer is B.
Step-by-step explanation:
According to the given data we have the following:
sample size, h=600
probability against increase tax p=0.45
The probability that in a sample of 600 people, more that 360 people will be against increasing taxes.
We find that P(P>360/600)=P(P>0.6)
The sample proposition of p is approximately normally distributed mith mean p=0.45
standard deviation σ=√P(1-P)/n=√0.45(1-0.45)/600
If x≅N(u,σ∧∧-2), then z=(x-u)/σ≅N(0,1)
Now, P(P>0.6)=P(<u>P-P</u> > <u>0.6-0.45)</u>
σ √0.45*0.55/600
=P(Z> <u>0.6-0.45)</u>
√0.45*0.55/600
Izzy because her word rate is 98, which is more than 95 (the minimum).
Answer:
Hey can someone help me out thank! :D ITS DUE TODAY PLZZZ!!!!
1. Use the integer multiplication facts in their integer bubble to create six related integer division facts.
2.The quotient of any two integers (with a non zero divisor) will be a rational number. If and are integers, then - (p/q)= (---)=(----)
3. Mrs. McIntire, a seventh-grade math teacher, is grading papers. Three students gave the following responses to the same math problem: 1/-2 -(1/2) -1/2
4.On Mrs. McIntire’s answer key for the assignment, the correct answer is −0.5. Which student answer(s) is (are) correct? Explain.
Step-by-step explanation:
The answer is 0.1 i think
Answer: $70 per year.
Step-by-step explanation:
Let's say that x is the number of years that has passed and y is how much the stamp is worth.
So we know that in zero years the stamp was worth $420 because that is the time Sheri gave her brother Sam the stamp. That could bring up the coordinates (0,420) .
Now we know that in 8 years it was worth $980 and that could be the coordinates (8,980)
To find the rate of change we need to find the different between the y value and divide it by the difference in the x values.
420 - 980 = -560
0-8 = -8
-560/-8 = 70
The rate of change is 70 which means that it grew by $70 every year.
