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Evgesh-ka [11]
2 years ago
7

Consider the random permutations of [1..6]. Let A be the event that the number in the first position of such a random permutatio

n is 6, and let B be the event that the number in the last position of such a random permutation is 1. Calculate Pr[A | B].
Mathematics
1 answer:
REY [17]2 years ago
7 0

Answer:

Pr[A | B] = 0.2

Step-by-step explanation:

If we have a permutation of {1,2,3,4,5,6} that ends in 1, then we will have only 5 possibilities for the first spot, 2,3,4,5 and 6. All of them equally probable. Thus, the probability that in the first position of a random permutation there is a 6, giving that in the last position there is a 1 is 1/5 = 0.2

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anygoal [31]

Answer:

As a whole number, 2.

As a whole number with a remainder, 2 R12.

Precisely 2.28571429 if you want to get specific.

Step-by-step explanation:

96 ÷ 42 = 2 R12

or

96 ÷ 42 = 2.28571429

Hope this helps! :)

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PLEASE HELP!!! Pr-Cal Question 20 points
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Answer:

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3 years ago
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7nadin3 [17]

Answer:

0

Step-by-step explanation:

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2 years ago
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Please explain this to me UwU
ki77a [65]
Each answer possibility is a coordinate and represents a variety of an (x,y) point. The equation states that y = 32x + 27, so to find the correct answer, u must find the (x,y) coordinate that makes each side equal to the other. Plug in each number accordingly...

(y) = 32(x) + 27

a. (248) = 32(8) + 27

b. (379) = 32(11) + 27

c. (354) = 32(6) + 27

d. (288) = 32(9) + 27

now it’s just a matter of simplifying to see which equation is true.

a. 248 =/ 283

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c. 354 =/ 219

d. 288 =/ 315

The only equation that is true is B.
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3 years ago
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In a week, 16 hens laid 64 eggs. what is the unit rate for eggs per hen?
Sveta_85 [38]

Answer:

4 eggs per hen

Step-by-step explanation:

You would need to divide the total number of eggs by the number of hens to see how many each one would produce:

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1 year ago
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