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Evgesh-ka [11]
3 years ago
7

Consider the random permutations of [1..6]. Let A be the event that the number in the first position of such a random permutatio

n is 6, and let B be the event that the number in the last position of such a random permutation is 1. Calculate Pr[A | B].
Mathematics
1 answer:
REY [17]3 years ago
7 0

Answer:

Pr[A | B] = 0.2

Step-by-step explanation:

If we have a permutation of {1,2,3,4,5,6} that ends in 1, then we will have only 5 possibilities for the first spot, 2,3,4,5 and 6. All of them equally probable. Thus, the probability that in the first position of a random permutation there is a 6, giving that in the last position there is a 1 is 1/5 = 0.2

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Answer:

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Step-by-step explanation:

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sorry if this doesnt make sense

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8 0
3 years ago
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I'm doing Quadratic formula and I've simplified it down to the equation at the bottom. What do I do after? Is that my answer bec
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6 0
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