Ask question

Ask question

All categories

11111nata11111 [884]

3 years ago

8

PLEASEE HELPPPP!!! ahhhhh

1 answer:

Agata [3.3K]3 years ago

8 0

(1,5)

To find this, do the opposite of how you got to (4,5).

Move right 2 units instead of left.

Move left 5 units instead of right.

Now, your on the point (1,5).

To check this, do what they said. (Move left 2 units and right 5 units) If its correct you end up on (4,5)

You might be interested in

1.01<0.99 true,4.5=4.50 true, 3.5<3.39 true?, lastly is 1.51>1.15 true?

kirza4 [7]

No, yes, no, yes

What part of comparing number values do you not understand? Most folks figure out enough about place value to be able to answer this by 3rd grade. If there's something about this question that really stumps you, please advise in the comments.

5 0

3 years ago

Classify △ABC

tensa zangetsu [6.8K]

Answer:

b and d

Step-by-step explanation:

4 0

3 years ago

What is the solution for x in the given equation? sgrt9x+7+sgrt2x=7

aliya0001 [1]

X=2

Hope that helps!
(Please Mark as Brainliest!)

8 0

3 years ago

Solve the system and give your answer as a coordinate point in the form (k, c) k+c=100 51k+11c=2500

Aleks [24]

Answer:

k = 35, c = 65

Step-by-step explanation:

Solve the following system:

{c + k = 100 | (equation 1)

{11 c + 51 k = 2500 | (equation 2)

Swap equation 1 with equation 2:

{11 c + 51 k = 2500 | (equation 1)

{c + k = 100 | (equation 2)

Subtract 1/11 × (equation 1) from equation 2:

{11 c + 51 k = 2500 | (equation 1)

{0 c - (40 k)/11 = -1400/11 | (equation 2)

Multiply equation 2 by -11/40:

{11 c + 51 k = 2500 | (equation 1)

{0 c+k = 35 | (equation 2)

Subtract 51 × (equation 2) from equation 1:

{11 c+0 k = 715 | (equation 1)

{0 c+k = 35 | (equation 2)

Divide equation 1 by 11:

{c+0 k = 65 | (equation 1)

{0 c+k = 35 | (equation 2)

Collect results:

Answer: {c = 65 , k = 35

5 0

3 years ago

Help! Pls I cant solve it help me with explanation also pls.

stich3 [128]

Given:

The expression is

$\dfrac{2}{a-2}-\dfrac{8}{a^2-4}$

To find:

The simplified form of the given expression.

Solution:

We have,

$\dfrac{2}{a-2}-\dfrac{8}{a^2-4}$

It can be written as

$=\dfrac{2}{a-2}-\dfrac{8}{a^2-2^2}$

$=\dfrac{2}{a-2}-\dfrac{8}{(a-2)(a+2)}$ $[\because a^2-b^2=(a-b)(a+b)]$

Taking LCM, we get

$=\dfrac{2(a+2)-8}{(a-2)(a+2)}$

$=\dfrac{2a+4-8}{(a-2)(a+2)}$

$=\dfrac{2a-4}{(a-2)(a+2)}$

$=\dfrac{2(a-2)}{(a-2)(a+2)}$

Cancel out the common factors.

$=\dfrac{2}{a+2}$

Therefore, the simplified form of the given expression is $\dfrac{2}{a+2}$ .

7 0

3 years ago