Me to I was doing the work but just lost it I will try again
I would go with D. Hope that helps :)
Answer:
Step-by-step explanation:
Domain x^2 - 9 {Solution: - infinity < x < infinity}
Interval notation (- infinity, infinity)
Range of x^2 - 9 (Solution: f(x) is greater than or equal to - 9)
Interval notation (-9, infinity)
Axis interception points of x^2 - 9:
X- intercepts (3, 0) (-3, 0)
Y-intercepts (0, -9)
Vertex of x^2 - 9: Minimum (0, -9)
Solve for f:
f (x) = x^2 - 9
Step 1: Divide both sides by x.
fx / x = x^2 - 9 / x
f = x^2 - 9 / x
Answer:
f = x^2 - 9 / x
Answer:
p(r+1)
Step-by-step explanation:
Hope this helps
-10, -1.75, -3/4, 1/2, 3, 9
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-3/4 converts to -0.75,
and 1/2 converts to 0.5. With -10 being farthest from zero on the number line, it would be the smallest. -1.75 would be the second smallest. Keeping in mind that -3/4 converts to -0.75, it would be the 3rd smallest. 1/2, or 0.5 would be greater, as it is the smallest POSITIVE number. Then you do 3, as it as a whole number, but still not the greatest. 9 would be the greatest.
hope i was helpful;-)