Answer:
A) Divide 20 by 2 and then add 8 to the result
Step-by-step explanation:
D
Remember starts at zero slope is up 4 right 1
Y= 4/1x+0
Y=4x
Answer:
Step-by-step explanation:
The probability of getting one even and one odd is the sum of probability of getting even and of getting odd and even. Since there are 3 even or odd on each die out of six numbers you have
P(EO)(3/6)(3/6)=1/4 and P(OE)=(3/6)(3/6)=1/4 so 1/4+1/4= 1/2
or you can find the probability of getting two odds or two evens and subtract that from 1
P(EE)=(3/6)(3/6)=1/4, P(OO)=(3/6)(3/6)=1/4
P(EO)=1-1/4-1/4=1/2
Answer:
In this example, if k = -7, this relationship is not a function, since x = -7 would have both y = 2 and y = 0.
Step-by-step explanation:
Requirement to be a function:
For a relationship to be a function, all values of x must have only one corresponding value of y.
In this question:
For x = -7, y = 2
For x = -1, y = 0
For x = 4, y = 0
For x = k, y = 0
A value of x must not have more than 1 value of y.
In this example, if k = -7, this relationship is not a function, since x = -7 would have both y = 2 and y = 0.
Answer:
Step-by-step explanation:
Use the zero-interval test [test point (0, 0)] to verify them as false or true, and to determine whether we shade the shared opposite portions [a shared portion that does NOT contain the origin] or the shared portions that DO contain the origin:
![\displaystyle 0 < -3[0] - 2 → 0 ≮ -2](https://tex.z-dn.net/?f=%5Cdisplaystyle%200%20%3C%20-3%5B0%5D%20-%202%20%E2%86%92%200%20%E2%89%AE%20-2)
So, this system will be shaded in a shared opposite portion.
*NOTE; Both inequalities have an identical y-intercept of ![\displaystyle [0, -2],](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B0%2C%20-2%5D%2C)
so both inequalities must intersect the y-axis at and since there are already lines labeled as <em>dashed</em><em> </em>and solid, we do not have to worry about it in this case.
** None of the other graphs match this, so the bottom right graph has to be it, considering it cut off.
I am joyous to assist you anytime.
