Answer:
Here we can use the relationship:
Distance = time*speed.
When Jose walks, his speed is 4 mph.
Then if he walks for X hours, the distance that he will travel is:
D = 4mph*X
When Jose runs, his speed is 8mph.
Then if he runs for T hours, the distance that he will travel is:
D´ = 8mph*Y
And we know that he travels in total 20 miles, then we must have that:
D + D´= 20mi
This leads to:
4mph*X + 8mph*Y = 20mi
Where X is the time that he walked, and Y is the time that he runed.
Then the equation that represents the different amounts of times that Jose runs and walks is:
4mph*X + 8mph*Y = 20mi
Where we can not really find the solutions for Y and X, because there is only one equation and two variables.
Answer:
(x + 6)² + (y - 2)² = 75
Step-by-step explanation:
The equation of a circle in standard form is
(x - h)² + (y - k)² = r²
where (h, k) are the coordinates of the centre and r is the radius
here (h, k) = (- 6, 2) and r = 5
, hence
(x - (- 6))² + (y - 2)² = (5
)², that is
(x + 6)² + (y - 2)² = 75
Answer:
r=4/63
Step-by-step explanation:
Divide each term in 9r=47 by 9 and simplify.
D is the you looking have a nice day
Answer:
Queda 2/5 del depósito del agua para el resto de la semana.
Step-by-step explanation:
(This problem is presented in Spanish and for that reason explanation will be held in the same language)
La capacidad remanente del depósito de agua se obtiene mediante una resta de fracciones. Es decir:





Queda 2/5 del depósito del agua para el resto de la semana.