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lawyer [7]
3 years ago
10

when asked to factor the trinomial 8x2-8x-16, a student gives the answer (x-2)(x+1. What is one thing wrong with this answer?

Mathematics
1 answer:
VashaNatasha [74]3 years ago
5 0
One thing wrong is there is not closing parenthasees after x+1
and also, if you multiply it out, the answer is not 8x^2-8x-16 so the factored form given is worng

the real factored out form is 8(x-2)(x+1)
that person forgot the 8 in the front
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timofeeve [1]

Given:

\frac{\frac{p^2-p-2}{2p^2+3p+1}}{\frac{p^2-3p+2}{p^2+5p-6}}

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1 year ago
19=h/3 -8 whats h??
creativ13 [48]
First add the 8 to both sides, canceling out the 8 in the right and adding it to the 19 on the left, making it 27. Multiplying undoes division so, After that, multiply by three on both sides, canceling out the three on the right and multiply 27 by 3, making it 81.

8 0
3 years ago
Two points on the line are (0, 4) and (7, 18). Use the points to first determine the slope and y-intercept. Then write the equat
Nadya [2.5K]

9514 1404 393

Answer:

  a.  m = 2; y intercept = (0, 4); y = 2 x + 4

Step-by-step explanation:

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2 years ago
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
What is a true statement about negative exponents?
Nadya [2.5K]

Answer:

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Step-by-step explanation:

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This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So a^{3} would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase a^{3} to a^{5}, you would have to multiply a with a^{3} two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease a^{5} to a^{2}, you would have to divide a^{5} by a 3 times.

If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: \frac{1}{a^{3}} means that you are dividing 1 by a 3 times.

Hope this helps.

3 0
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