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3 years ago

when asked to factor the trinomial 8x2-8x-16, a student gives the answer (x-2)(x+1. What is one thing wrong with this answer?

1 answer:

5 0

One thing wrong is there is not closing parenthasees after x+1
and also, if you multiply it out, the answer is not 8x^2-8x-16 so the factored form given is worng

the real factored out form is 8(x-2)(x+1)
that person forgot the 8 in the front

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${z}^{ \frac{1}{2} }$

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$\huge \sqrt[5]{ {z}^{4} {z}^{ - \frac{3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{4 - \frac{3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{ \frac{8 - 3}{2} } } \\ \\ = \huge \sqrt[5]{ {z}^{ \frac{5}{2} } } \\ \\ = \huge {z}^{ \frac{5}{2} \times \frac{1}{5} } \\ \\ = \huge {z}^{ \frac{1}{2} }$

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Eric was rock climbing. At one point, he stopped and climbed straight down 2\dfrac{1}{2}2

nikitadnepr [17]

The equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

We know that in mathematics, subtraction means removing something from a group or a number of things. What is left in the group gets smaller when we subtract. The minuend is the first element we use. The subtrahend is the part that is being removed. The difference is the portion that remains after subtraction.

Assume that "negative" means climbing down and "positive" means climbing up. We must locate the elevation change in this area.

Given that Eric climbed straight down $2\frac{1}{2}$ meters. So we can write $-2\frac{1}{2}$ .

Again Eric climbed straight up $6\frac{3}{4}$ meters. So, we can write $6\frac{3}{4}$ .

Then the change = $-2\frac{1}{2}+6\frac{3}{4}$

= $-\frac{(2*2+1)}{2}+\frac{6*4+3}{4}$

= $-\frac{5}{2} +\frac{27}{4}$

= $\frac{-(5*2)+27}{4}$

= $\frac{-10+27}{4}$

= $\frac{17}{4}$

= $\frac{4*4+1}{4}$

= $4\frac{1}{4}$

Therefore, the equation that matches the given situation is $-2\frac{1}{2}+6\frac{3}{4}=?$ . So, after two moves, Eric's elevation changed $4\frac{1}{4}$ meters above.

Learn more about subtraction here -

brainly.com/question/24116578

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