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Roman55 [17]
3 years ago
12

Please help :(( i will mark brainliest

Mathematics
1 answer:
MrMuchimi3 years ago
6 0

Answer:

See explanation

Step-by-step explanation:

x <= 3.9 means that x is less than or equal to 3.9

So lets look at each value:

x = 4.1      4.1 is not less than or equal to 3.9, so x = 4.1 is not a part of the solution set

x = -3.9       -3.9 is less than or equal to 3.9, so x = -3.9 is a part of the solution set

x = 3.9          3.9 is equal to 3.9, so x = 3.9 is a part of the solution set

x = 4            4 is not less than or equal to 3.9, so x= 4 is not a part of the solution set

x = 4.3            4.3 is not less than or equal to 3.9, so x= 4.3 is not a part of the solution set

x = 3.8            3.8 is less than 3.9, so x = 3.8 is a part of the solution set

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lys-0071 [83]

Answer:

\bold{x =cos\theta}\\\bold{y=sin\theta}

Step-by-step explanation:

The given system of linear equations is:

(cos\theta)x+(sin\theta)y=1\\(-sin\theta)x+(cos\theta)y=0

We have to solve the equations for the values of x, y.

Let us use elimination method in which we eliminate one of the variables from the two variables.

For this, let us multiply the first equation by sin\theta and second equation by cos\theta

Now, the equations become:

(cos\theta.sin\theta)x+(sin\theta.sin\theta)y=sin\theta\\\Rightarrow (cos\theta.sin\theta)x+(sin^2\theta)y=sin\theta ....... (1)\\\\(-sin\theta.cos\theta)x+(cos\theta.cos\theta)y=0\\\Rightarrow (-sin\theta.cos\theta)x+(cos^2\theta)y=0 ..... (2)

Now, let us add (1) and (2):

(sin^2\theta)y+(cos^2\theta)y=sin\theta\\\Rightarrow (sin^2\theta+cos^2\theta)y=sin\theta\\\Rightarrow (1)y=sin\theta\\\Rightarrow y = sin\theta

Using the equation:

(-sin\theta)x+(cos\theta)y=0

Putting value of y:

\Rightarrow (-sin\theta)x+(cos\theta)sin\theta=0\\\Rightarrow (sin\theta)x=(cos\theta)sin\theta\\\Rightarrow x = cos\theta

So, the answer to the system of linear equations is:

\bold{x =cos\theta}\\\bold{y=sin\theta}

7 0
3 years ago
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