Pls helpp will give brainliest
1 answer:
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So I'm going to assume that this question is asking for <u>non extraneous solutions</u>, or solutions that are found in the equation <em>and</em> are valid solutions when plugged back into the equation. So firstly, subtract 2 on both sides of the equation:
Next, square both sides:
Next, subtract x and add 2 to both sides of the equation:
Now we are going to be factoring by grouping to find the solution(s). Firstly, what two terms have a product of 6x^2 and a sum of -5x? That would be -3x and -2x. Replace -5x with -2x - 3x:
Next, factor x^2 - 2x and -3x + 6 separately. Make sure that they have the same quantity on the inside of the parentheses:
Now you can rewrite the equation as
Now, apply the Zero Product Property and solve for x as such:
Now, it may appear that the answer is C, however we need to plug the numbers back into the original equation to see if they are true as such:
Since both solutions hold true when x = 2 and x = 3, <u>your answer is C. x = 2 or x = 3.</u>
Here you go kind brain
Answer:
Step-by-step explanation:
We are given that a license plate consist of 5 digits and 5 uppercase letters
Digits used=0,1,2,..9
Total number of letters=26
Repetition is not allowed
Total number of odd digits=(1,3,5,7,9)=5
The first place filled by 5
Second place filled by 4
Third place filled by 8
Fourth place filled by 7
Fifth place filled by 6
Sixth place filled by 26
Seventh place filled by 25
Eighth place filled by 24
Ninth place filled by 23
Tenth place filled by 22
Total number of possible different license plates ==