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hodyreva [135]
3 years ago
6

What is the measurement of 6?A) 45°B) 54°C) 117°D) 126°​

Mathematics
1 answer:
Arlecino [84]3 years ago
3 0

Answer:

A.) 45*

Hope this helps!

Step-by-step explanation:

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Nine out of ten students prefer math class over lunch. How many students do not prefer math if 200 students were asked
Nimfa-mama [501]

Answer:

i think probably 20

Step-by-step explanation:

if 200 students, students do not prefer math 10/100 × 200 = 20

4 0
2 years ago
Determine the fraction of total interest owed using the rule of 78. After the six month of a 12 month loan, the numerator is: {(
Dima020 [189]

Answer:

The fraction of total interest owed is  \frac{57}{78}

The value of it to the nearest tenth is 73.1%

Step-by-step explanation:

Let us solve it using the rule of 78

∵ The loan = 12 month

∵ The numerator is after 6 month

- Substitute n by 1 in each bracket

∴ The numerator = {(1 + 11) + (1 + 10) + (1 + 9) + (1 + 8) + (1 + 7) + (1 + 6)}

∴ The numerator = {12 + 11 + 10 + 9 + 8 + 7}

∴ The numerator = {57}

∴ The numerator of the fraction is 57

∵ The denominator = {(n) + (n + 1) + (n + 2) + .......... + (n + 11)}

- substitute n by 1 in each bracket

∴ The denominator = {1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 + 11 + 12}

∴ The denominator = {78}

∴ The denominator of the fraction is 78

The fraction of total interest owed is  \frac{57}{78}

Now find the value of the fraction

∵ The fraction = \frac{57}{78}

∴ Its value = 0.7307692308 × 100%

∴ Its value = 73.07692308%

- Round it to the nearest tenth

∴ Its value = 73.1%

The value of it to the nearest tenth is 73.1%

5 0
3 years ago
What is the surface area using integrals of these two lines. Y=10-x^2 and Y=x^2+2 from the bounds x=2 and x=-2.
Lelu [443]

Check the picture below.

\bf \displaystyle\int\limits_{-2}^{2}~[\stackrel{\textit{above function}}{(10-x^2)}~~-~~\stackrel{\textit{below function}}{(x^2+2)}]dx\implies \int\limits_{-2}^{2}~(10-x^2-x^2-2)dx \\\\\\ \displaystyle\int\limits_{-2}^{2}~(8-2x^2)dx\implies \left. 8x\cfrac{}{} \right]_{-2}^{2}-\left. \cfrac{2x^3}{3} \right]_{-2}^{2} \\\\\\ ([16]-[-16])~~-~~\left( \left[ \cfrac{16}{3} \right]-\left[ -\cfrac{16}{3} \right]\right)\implies (32)~~-~~\left( \cfrac{32}{3} \right) \\\\\\ \cfrac{64}{3}\implies 21\frac{1}{3}

5 0
3 years ago
Devon uses the equation c = 9.74...
guajiro [1.7K]

Answer:

Step-by-step explanation:

How is 2 weeks for quick

8 0
3 years ago
Avani wrote the linear equation y = 5 x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5 x + 4 and t
Margarita [4]

Avani wrote the linear equation y = 5x + 4. Then, she wrote the equation of the line that is perpendicular to y = 5x+ 4 and that passes through (15,–2). If her new equation is in the form  y-\frac{1}{5}x+b, what is the value of b?

\bf y=mx+b

  • m is the slope
  • b is the y-intercept

The equation of a line that is perpendicular to another line always has the opposite reciprocal slope. In the original equation, the slope is 5. The opposite of 5, which refers to the sign, is -5. The reciprocal of -5 is -1/5. That means the slope of the new line is -1/5.

The perpendicular line:

  • Has a slope of -\frac{1}{5}
  • Passes through the point (15, -2)

To find the equation of a line that passes through a specific point, you need to use slope-intercept form.

\bf y-y_{1} =m(x-x_{1})

  • y₁ is the y-value of the point
  • m is the slope
  • x₁ is the x-value of the point

y₁ is -2, m is -1/5,  and x₁ is 15.

Substitute the known values into the equation:

y-(-2)=-\frac{1}{5}(x-15) \rightarrow y+2= -\frac{1}{5}(x-15)

Open the parentheses and distribute:

-\frac{1}{5}(x-15) \rightarrow -\frac{1}{5} \cdot x\ +  -\frac{1}{5} \cdot -15 \rightarrow -\frac{1}{5}x +3

The new equation will be:

y+2=-\frac{1}{5}x+3

Lastly, you need to move the positive 2 to the other side to keep it in y = mx + b form.

y+2-2=-\frac{1}{5}x+3-2 \rightarrow y=-\frac{1}{5}x+1

The equation of the perpendicular line is:

\bf y=-\frac{1}{5}x+1

The value of b is 1.

5 0
3 years ago
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