Answer:
Constant of proportionality(X:Y) = 1:6
Step-by-step explanation:
Given:
X- 5, 6, 7, 8, 9
Y- 30, 36, 42, 48, 54
Find:
Constant of proportionality
Computation:
X/Y = 5/30 = 6/36 = 7/42 = 8/48 = 9/54
X/Y = 1/6 = 1/6 = 1/6 = 1/6 = 1/6
So;
Constant of proportionality(X:Y) = 1:6
Answer:
x=9
Step-by-step explanation:
The expression is for the interior angle of the hexagon; one interior angle is equal to .
Since an interior angle of a hexagon measures 120°, we have the equality
.
Now it is just a matter of solving for
11x=120-21
11x=99
x=99/11
x=9
Answer: Option 'D' is correct.
Step-by-step explanation:
I need to borrow some money from my parents as my deficit has <u>grown or increased.</u>
If deficit of any individual increases , means, he is short of money.
So, he needs to borrow from his parents.
Hence, Option 'D' is correct.
Answer:
L = 25.959 inches
Step-by-step explanation:
Volume of first cube = 375 inch³
Volume of second cube = 648 inch³
Volume of third cube = 1029 inch³
We need to find the length of the stack of the cube shaped block.
We know that,
The volume of a cube = a³ (a is side of a cube)
![a_1=\sqrt[3]{375} \\\\=7.211\ \text{inches}](https://tex.z-dn.net/?f=a_1%3D%5Csqrt%5B3%5D%7B375%7D%20%5C%5C%5C%5C%3D7.211%5C%20%5Ctext%7Binches%7D)
![a_2=\sqrt[3]{648 } \\\\=8.653\ \text{inches}](https://tex.z-dn.net/?f=a_2%3D%5Csqrt%5B3%5D%7B648%20%7D%20%5C%5C%5C%5C%3D8.653%5C%20%5Ctext%7Binches%7D)
![a_3=\sqrt[3]{1029} \\\\=10.095\ \text{inches}](https://tex.z-dn.net/?f=a_3%3D%5Csqrt%5B3%5D%7B1029%7D%20%20%5C%5C%5C%5C%3D10.095%5C%20%5Ctext%7Binches%7D)
Hence, the total length of the stack is :
L = 7.211 + 8.653 + 10.095
= 25.959 inches
Hence, this is the required solution.
Let's begin by listing the first few multiples of 4: 4, 8, 12, 16, 20, 24, 28, 32, 36, 38, 40, 44. So, between 1 and 37 there are 9 such multiples: {4, 8, 12, 16, 20, 24, 28, 32, 36}. Note that 4 divided into 36 is 9.
Let's experiment by modifying the given problem a bit, for the purpose of discovering any pattern that may exist:
<span>How many multiples of 4 are there in {n; 37< n <101}? We could list and then count them: {40, 44, 48, 52, 56, 60, 64, 68, 72, 76, 80, 84, 88, 92, 96, 100}; there are 16 such multiples in that particular interval. Try subtracting 40 from 100; we get 60. Dividing 60 by 4, we get 15, which is 1 less than 16. So it seems that if we subtract 40 from 1000 and divide the result by 4, and then add 1, we get the number of multiples of 4 between 37 and 1001:
1000
-40
-------
960
Dividing this by 4, we get 240. Adding 1, we get 241.
Finally, subtract 9 from 241: We get 232.
There are 232 multiples of 4 between 37 and 1001.
Can you think of a more straightforward method of determining this number? </span>
