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jeka94
3 years ago
13

Sara has six necklaces, but her mother will only allow her to wear two at a time. How many different combinations of two necklac

es can Sara wear?
Mathematics
2 answers:
MatroZZZ [7]3 years ago
6 0

Answer:

15 different combinations

Step-by-step explanation:

Sara has six necklaces, but her mother will allow her to wear two at a time.

So we calculate different combinations of two necklaces by this formula:

\frac{n!}{r!(n-r)!}

Where n = 6 and r = 2

Now put the values

\frac{6!}{2!(6-2)!}

\frac{6\times 5\times 4\times 3\times 2\times 1}{2!(6-2)!}

\frac{720}{2\times 1(4)!}

\frac{720}{2\times 1(4\times 3\times 2\times 1)}

\frac{720}{2(24)}

\frac{720}{48} = 15 combinations

Sara can wear 15 different combinations of two necklaces.

GuDViN [60]3 years ago
5 0

6C2 = (6 x5)/(2 x 1) = 15 difference combinations

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