Answer:
1. 3rd degree
2. No degree
3. First degree
4. 8th degree
Step-by-step explanation:
Hope this helps!
Answer:
a) The function is constantly increasing and is never decreasing
b) There is no local maximum or local minimum.
Step-by-step explanation:
To find the intervals of increasing and decreasing, we can start by finding the answers to part b, which is to find the local maximums and minimums. We do this by taking the derivatives of the equation.
f(x) = ln(x^4 + 27)
f'(x) = 1/(x^2 + 27)
Now we take the derivative and solve for zero to find the local max and mins.
f'(x) = 1/(x^2 + 27)
0 = 1/(x^2 + 27)
Since this function can never be equal to one, we know that there are no local maximums or minimums. This also lets us know that this function will constantly be increasing.
9514 1404 393
Answer:
(c) 27x^11 +51x^7 +9x^6 -60x^5 +17x^2 -20
Step-by-step explanation:
As with many multiple-choice questions, you only need to look at something that will discriminate the correct answer from the wrong one.
The highest-degree product term is the product of the highest-degree terms in the factors:
(3x^5)(9x^6) = 27x^11
This matches choice C only.
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In case you're interested in actually performing the rest of the multiplication, the distributive property applies.
(1 +3x^5)(17x^2 +9x^6 -20)
= 1(17x^2 +9x^6 -20) +3x^5(17x^2 +9x^6 -20)
= 17x^2 +9x^6 -20 +51x^7 +27x^11 -60x^5
Writing these terms in order of decreasing exponents gives ...
= 27x^11 +51x^7 +9x^6 -60x^5 +17x^2 -20
Answer:
168
Step-by-step explanation:
You just need to triple the answer to get 168.