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2 years ago

Whats 100,002÷13 dont try calculator or paper

Mathematics

2 answers:

balandron [24]2 years ago

6 0

100,002 divded by 13 will be 7692 when estimated

erica [24]2 years ago

5 0

7692 when estimated. Good luck

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Find the increasing functions. Then arrange the increasing functions in order from least to greatest rate of change. (not all of

Aleksandr [31]

Answer:

to a function is increasing we have to find the slope of the function

the higher the slope the faster the growth

Step-by-step explanation:

slope = 5/2. which is 2.5
slope 2 = -1/2 which is -0.5
slope 3 = 3/2 which is 1.5
slope 4 = 1/2 which is 0.5
slope 5= 4/3 which is 1.33
slope 6 = 3/4 which is 0.75

so the function in increasing order

y= -1/2x + 1/2

y= 1/2x - 2

y=3/4x - 10

y=4/3x -7/3

y=3/2x-11/2

y=5/2x +10

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2 years ago

What are all the common factors?

lord [1]

Answer:

2,3,6

Step-by-step explanation:

8 0

3 years ago

I need these questions to be answered correctly plz tryna get my grade up

Reil [10]

Answer:

1. 81

2. 4 (square root of) 25^3

3. 30 (square root of) 10

6 0

2 years ago

There are 4 people at a party. Consider the random variable X=’number of people having the same birthday ’ (match only month, N=

yulyashka [42]

Answer:

S = {0,2,3,4}

P(X=0) = 0.573 , P(X=2) = 0.401 , P(x=3) = 0.025, P(X=4) = 0.001

Mean = 0.879

Standard Deviation = 1.033

Step-by-step explanation:

Let the number of people having same birth month be = x

The number of ways of distributing the birthdays of the 4 men = (12*12*12*12)

The number of ways of distributing their birthdays = 12⁴

The sample space, S = { 0,2,3,4} (since 1 person cannot share birthday with himself)

P(X = 0) = $\frac{12P4}{12^{4} }$

P(X=0) = 0.573

P(X=2) = P(2 months are common) P(1 month is common, 1 month is not common)

P(X=2) = $\frac{3C2 * 12P2}{12^{4} } + \frac{4C2 * 12P3}{12^{4} }$

P(X=2) = 0.401

P(X=3) = $\frac{4C3 * 12P2}{12^{4} }$

P(x=3) = 0.025

P(X=4) = $\frac{12}{12^{4} }$

P(X=4) = 0.001

Mean, $\mu = \sum xP(x)$

$\mu = (0*0.573) + (2*0.401) + (3*0.025) + (4*0.001)\\\mu = 0.879$

Standard deviation, $SD = \sqrt{\sum x^{2} P(x) - \mu^{2}} \\SD =\sqrt{ [ (0^{2} * 0.573) + (2^{2} * 0.401) + (3^{2} * 0.025) + (4^{2} * 0.001)] - 0.879^{2}}$

SD = 1.033

4 0

3 years ago

What combination of transformations is shown below?

muminat

Answer:

B. or the second one

Step-by-step explanation:

8 0

2 years ago

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