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Alexxandr [17]
4 years ago
15

Are the expressions -0.5(3x + 5) and -1.5x + 2.5 equivalent? Explain why or why not

Mathematics
2 answers:
Gelneren [198K]4 years ago
7 0

Answer:

Step-by-step explanation:

-0.5(3x + 5)   and   -1.5x + 2.5

-0.5(3x + 5)...distribute the -0.5 thru the parenthesis

-1.5x - 2.5

no, these are not equivalent.... one is -1.5x + 2.5 and the other is -1.5x - 2.5....not the same

Anna71 [15]4 years ago
3 0

Answer:

Both expressions are not equal

Step-by-step explanation:

First expression is

-0.5(3x + 5)

By multiplying

-1.5x - 2.5

2nd expression is

-1.5x + 2.5

Only Sign is different with 2.5 in both cases

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The length of a rectangle exceeds its width by 1
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Answer:

Width equals 11, and length equals 12.

Step-by-step explanation: It is helpful to memorize your multiplication tables up to 12. I personally couldn't figure out a formula for this, but I knew that 12 x 11 equals 132, and the length is greater than the width, so length is 12 and width is 11. Hopefully somebody else can figure it out. P.S. I meant the formula, not the answer, my answer is correct.

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What is the value of x in the equation three-fourths (one-fourth x 8) minus (one-half x 2) = startfraction 3 over 8 endfraction
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The value of x in the equation is x=-44.

The given equation is \frac{3}{4}\left(\frac{1}{4}x+8\right)-\left(\frac{1}{2}x+2\right)=\frac{3}{8}(4-x)-\frac{1}{4}.

An algebraic expression in mathematics is an expression that's made from variables and constants, together with algebraic operations (addition, subtraction, etc.). Expressions are made of terms.

Firstly, apply the distributive property as a(b+c)=ab+ac and get

\begin{aligned}\frac{3}{4}\times \frac{1}{4}x+\frac{3}{4}\times 8-\frac{1}{2}x-2&=\frac{3}{8}\times 4-\frac{3}{8}\times x-\frac{1}{4}\\ \frac{3x}{16}+6-\frac{x}{2}-2&=\frac{3}{2}-\frac{3x}{8}-\frac{1}{4} \end

Now, rearrange the terms by taking variable terms on the left-hand side and constant terms on the right-hand side as

\frac{3x}{16}-\frac{x}{2}+\frac{3x}{8}=\frac{3}{2}-\frac{1}{4}-6+2

Further, simplify the above expression by taking L.C.M as

\begin{aligned}\frac{3x-8x+6x}{16}&=\frac{6-1}{4}-4\\ \frac{x}{16}&=\frac{5-16}{4}\\ \frac{x}{16}&=\frac{-11}{4}\end

Then, multiply both sides with 4 and get

\begin{aligned}4\times \frac{x}{16}&=4\times \frac{-11}{4}\\ \frac{x}{4}&=\frac{-11}{1}\end

Furthermore, cross multiply both sides and get

x=-44

Hence, the value of x in the equation which is given \frac{3}{4}\left(\frac{1}{4}x+8\right)-\left(\frac{1}{2}x+2\right)=\frac{3}{8}(4-x)-\frac{1}{4} is x=-44.

Learn about algebraic expression from here brainly.com/question/8690932

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8 0
2 years ago
100 random students are surveyed outside of the student center on campus. Let V denote that the student has a Visa credit card a
mote1985 [20]

Answer:

(a) The value of P (M | V) is 0.30.

(b) The value of P (M^{c} | V) is 0.70.

(c) The value of P (V | M) is 0.375.

(d) The value of P(V^{c}|M) is 0.625.

Step-by-step explanation:

It is provided that,

<em>V</em> = a student has a Visa card

<em>M</em> = a student has a Master card

N = 100, n (<em>V</em>) = 40, n (<em>M</em>) = 32 and n (<em>V</em> ∩ <em>M</em>) = 12.

The probability of a student having visa card is:

P(V) = \frac{n(V)}{N}= \frac{40}{100}=0.40

The probability of a student having master card is:

P(M) = \frac{n(M)}{N}= \frac{32}{100}=0.32

The probability of a student having  visa card and a master card is:

P(V\cap M) = \frac{n(V\cap M)}{N}= \frac{12}{100}=0.12

The conditional probability of an event, say A, given that another event, say B, has already occurred is,

P(A|B)=\frac{P(A\cap B)}{P(B)}

(a)

Compute the probability that a student has a master card given that he/she has a visa card also, i.e. P (M | V) as follows:

P(M|V)=\frac{P(V\cap M)}{P(V)} =\frac{0.12}{0.40}=0.30

Thus, the value of P (M | V) is 0.30.

(b)

Compute the probability that a student does not have a master card given that he/she has a visa card also, i.e. P (M^{c} | V) as follows:

P (M^{c} | V)=1-P(M|V)=1-0.30=0.70

Thus, the value of P (M^{c} | V) is 0.70.

(c)

Compute the probability that a student has a visa card given that he/she has a master card also, i.e. P (V | M) as follows:

P(V|M)=\frac{P(V\cap M)}{P(M)} =\frac{0.12}{0.32}=0.375

Thus, the value of P (V | M) is 0.375.

(d)

Compute the probability that a student does not have a visa card given that he/she has a master card also, i.e. P(V^{c}|M) as follows:

P(V^{c}|M)=1-P(V|M)=1-0.375=0.625

Thus, the value of P(V^{c}|M) is 0.625.

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