PLEASE PLEASE help me out!!! Trying to get my grade up
2 answers:
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Answer:
Both are inverse pairs
Step-by-step explanation:
Question 11
(a) Rename g(x) as y
(b) Solve for x :
(c) Multiply each side by ⅝
(d) Switch x and y
(e) Rename y as the inverse function
(f) Compare with your function
f(x) and g(x) are inverse functions.
The graphs of inverse functions are reflections of each other across the line y = x.
In the first diagram, the graph of ƒ(x) (blue) is the reflection of g(x) (red) about the line y = x (black)
Question 12
h(x)= x - 2
(a) Rename h(x) as y
y = x - 2
(b) Solve for x:
x = y + 2
(c) Switch x and y
y = x + 2
(e) Rename y as the inverse function
h⁻¹(x) = x + 2
(f) Compare with your function
f(x) = x + 2
f(x) = h⁻¹(x)
h(x) and ƒ(x) are inverse functions.
The graph of h(x) (blue) reflects ƒ(x) (red) across the line y = x (black).
Answer: 15
<u>Step-by-step explanation:</u>
small: 5 12 13
middle: __ 36 39
large: 45 108 117
Notice that to get from the small to the large, multiplied by 9
5(9) = 45 12(9) = 108 13(9) = 117
That is because the sides are proportional
To get from small to middle, multiply by 3
5(3) = 15 12(3) = 36 13(3) = 39
To solve it using proportions: