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gulaghasi [49]
4 years ago
10

For circle C, CG = CE, CG is perpendicular to FB, and CE is perpendicular to DA. What conclusion can be made? a circle with cent

er C and chords FB and DA, a segment from C to chord FB intersects chord FB at G, and a segment from C to chord DA intersects chord DA at E
Mathematics
1 answer:
svetlana [45]4 years ago
8 0

Answer:

A circle with center C has chords FB and DA which are equidistant from C.

Step-by-step explanation:

A chord is a straight line drawn from a point on the circumference of a circle to another point on the circumference, without passing through the center of the circle.

From the given question, a circle center C has two chords FB and DA that are equidistant from the center of the circle. The distant of FB from C is CG and the distance of DA from C is CE. But CG = CE, which implies that the two chords have equal distant from the center of the circle.

Therefore line CG from center C intersects FB at G, and line CE from center C intersects DA at E.

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Question:

Select expression that is mathematically equivalent to

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d) x/(y - z) + a - b * c

Answer:

x/(y - z) + (a - b) * c

Step-by-step explanation:

Given

\frac{x}{y-z} + (a-b)*c

Required

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Start by writing y - z in bracket;

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When - is used as divide, it is equivalent to /

The given expression can then be rewritten as

x/(y - z) + (a - b) * c

Hence;

<em />\frac{x}{y-z} + (a-b)*c<em> is equivalent to </em>x/(y - z) + (a - b) * c<em />

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