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3 years ago

Using the Pythagorean Theorem, give an example of three sides of a right triangle

Mathematics

1 answer:

VikaD [51]3 years ago

8 0

Answer:

Two legs and an hypotenuse

Step-by-step explanation:

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Can someone answer this for me? Thanks!

MrRa [10]

Hiii :))

Answer is in the attachment.

Identity used :-

1) cosec² α = 1 + cot² α

Trigonometric Ratio :-

1) cot 30° = √3

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RainbowSalt2222 ☔

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2 years ago

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givi [52]

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3 years ago

How do i round 981,657 to the nearest ten thousand ?

Arlecino [84]

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3 years ago

The figure below shows square ABCD inscribed on square PQRM on a coordinate plane. Which of the following expressions represents

vova2212 [387]

The hypotenuse of the triangle is given by:
$CB ^ 2 = RC ^ 2 + RB ^ 2
$
Substituting values:
$CB ^ 2 = 2 ^ 2 + 4 ^ 2
$
Clearing CB we have:
$CB = \sqrt{ 2 ^ 2 + 4 ^ 2} 

 CB = \sqrt{ 4 + 16} 

 CB = \sqrt{20} 

 CB = \sqrt{4*5} 

 CB = 2\sqrt{5} 



$
Then, the perimeter of the triangle is:
$P = RB + RC + CB
$
Substituting values:
$P = 4 + 2 + 2 \sqrt{5} 

 P = 6 + 2 \sqrt{5}$
Answer:
the perimeter of triangle BRC in units is:
D.6 + 2√5

7 0

3 years ago

Read 2 more answers

1. Drag and drop an answer to each box to correctly complete the derivation of a formula for the area of a sector of a circle.

N76 [4]

Answer:-

Central angle , Ф/2π , A = Ф/2 r²

The ratio is 1/3 , V = 1/3 Bh

The equation of the circle in standard form is (x - 4)² + (k - 1)² = 25

Step-by-step explanation:

* Lets revise the rules of the area of the sector of a circle

- The area of the sector which has a central angle Ф° is

(Ф°/360°) × πr², where 360° is the measure of the circle and r is

the radius of the circle

- The area of the sector which has a central angle Ф radians is

(1/2) r²Ф

* Lets complete the missing in the 1st picture

- The ratio of the sector's area A to the circle's area is equal to the

ratio of the central angle to the measure of a full rotation of the circle

- A full rotation of a circle is 2π. This proportion can written as

A/πr² = Ф/2π

- Multiply both sides by πr² to get A = Ф/2 r² where Ф is the measure

of the central angle and r is the radius of the circle

* Lets revise the rules of the volume of the prism and the volume

of the pyramid, where they have the same base and height

- The volume of the prism = area of the base × its height

- The volume of the pyramid = 1/3 × area of the base × its height

- From them the ratio of the volume of the pyramid to the volume

of the prism is 1/3

- The formula of the volume of the prism is V = Bh, where B is the

area of the base and h is the height, the formula of the volume

of the pyramid is V = 1/3 Bh

* Lets revise the standard form of the equation of a circle with

center (h , k) and radius r

- The equation is: (x - h)² + (y - k)² = r²

∴ x² - 2hx + h² + y² - 2ky + k² - r² = 0

∵ x² - 8x + y² - 2y - 8 = 0

- Lets equate the two equation

∴ x² - 2hx + h² + y² - 2ky + k² - r² = x² - 8x + y² - 2y - 8 = 0

∵ -2h = -8 ⇒ ÷ -2

∴ h = 4

∵ -2k = -2 ⇒ ÷ -2

∴ k = 1

∵ h² + k² - r² = -8

∴ (4)² + (1)² - r² = -8

∴ 16 + 1 - r² = -8

∴ 17 - r² = -8 ⇒ subtract 17 from both sides

∴ -r² = -15 × -1

∴ r² = 25

* Substitute the values of h , k , r in the equation of the standard

form of the circle

∴ (x - 4)² + (k - 1)² = 25

* The equation of the circle in standard form is (x - 4)² + (k - 1)² = 25

8 0

3 years ago