Question

Assume that all possible “ABO” blood phenotypes are present in a human population that is in Hardy-Weinberg equilibrium. If the frequency of the “A” allele is 0.24, and the frequency of the individuals in the population with blood Type O is 0.38, what is the frequency of individuals with Type B blood in the population?

Answer 1

Answer:

the frequency of individuals with Type B blood in the population is 0.1977

Explanation:

Given:

Frequency of A allele is p = 0.24

Frequency of the individuals with blood type O is r = 0.38

Question: What is the frequency of individuals with Type B blood in the population, fB = ?

You need to apply the Hardy-Weinberg Equilibrium:

p²+q²+r²+2pq+2pr+2qr = 1

Here,

p, q and r are the frequencies of the alleles

Calculating the frequency of the allele q:

$r=\sqrt{0.38} =0.6164$

q = 1-p-r = 1-0.24-0.6164 = 0.1436

Frequency of individuals with type B blood:

$f_{B} =q^{2} +2qr=(0.1436)^{2} +(2*0.1436*0.6164)=0.1977$