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Brrunno [24]
3 years ago
15

What is the slope of a line that is perpendicular to a line whose equation 3y=-4x+2

Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0

For this case we have to by definition, if two lines are perpendicular then the product of its slopes is -1. That is to say:

m_ {1} * m_ {2} = - 1

We have the following equation:

3y = -4x + 2\\y = - \frac {4} {3} x + \frac {2} {3}

Thus, the equation is of the pending-intersection formy = mx + b

Where:

m: It's the slope

b: It is the cut-off point with the y axis

We have to:

m_ {1} = - \frac {4} {3}

Thus, we find m_ {2}:

m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {- \frac {4} {3}}\\m_ {2} = \frac {3} {4}

Thus, the slope of the line perpendicular to the given line is:

m_ {2} = \frac {3} {4}

ANswer:

m_ {2} = \frac {3} {4}

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