ANSWER:
a = 11
b = 2
Explaination:
We have two equations:
a = 5b + 1 .....................(1)
a = 3b + 5.....................(2)
Here we use substitution method in order to solve the set of equations.
put a=3b+1 to equation (1)
3b + 5 = 5b + 1
Solve for b
5 = 5b -3b + 1
5-1 =2b
4 = 2b
b = 2
Now put the value of b = 2 into the equation (1) or (2)
a = 5b + 1
a = 5(2) + 1
a = 10 + 1
a = 11
The midpoint formula is:
(point1 + point2)/2
1) (-2 + 12)/2 = 5
2) (-1 +5)/2 = 2
(0+2)/2 = 1
(2,1)
3) Sqrt of (x2-x1)^2 + (y2 - y1)^2
sqrt of (7 -1)^2 + (-7 - 1)^2
sqrt of (6)^2 + (-8)^2
sqrt of 36 + 64
sqrt of 100
10
Hope this helps!
First, find the radius of the circle. The radius of a circle is half the diameter. r=13/2=6.5
Second, use the equation A=pi * r^2 to find the area of the circle.
A=(3.14) * (6.5^2) = 132.665m^2
so the answer is 132.7 m^2.
