Answer:
Multiply row 1 by 
.
Step-by-step explanation:
The augmented matrix of the system of linear equation is described below:
![\left[\begin{array}{cccc}2&1&-1&-8\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D2%261%26-1%26-8%5C%5C0%262%263%26-6%5C%5C-%5Cfrac%7B1%7D%7B2%7D%20%261%261%26-4%5Cend%7Barray%7D%5Cright%5D)
Where 
, if we need to create 
, we need to multiply row 1 by , that is to say:
![\left[\begin{array}{cccc}1&\frac{1}{2} &-\frac{1}{2} &-4\\0&2&3&-6\\-\frac{1}{2} &1&1&-4\end{array}\right]](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bcccc%7D1%26%5Cfrac%7B1%7D%7B2%7D%20%26-%5Cfrac%7B1%7D%7B2%7D%20%26-4%5C%5C0%262%263%26-6%5C%5C-%5Cfrac%7B1%7D%7B2%7D%20%261%261%26-4%5Cend%7Barray%7D%5Cright%5D)
Hence, the correct answer is: Multiply row 1 by .
Answer:
57.39
[tex]440 \: ( 1 + \frac{5t}{46 + \: {t}^{2} } ) \\ 440 \: ( \frac{6t}{46 {t}^{2} } ) \: ( \: multiply \: 440 \times 6t) \\ \frac{2640}{46} \\ = 57.39 or 57.30
Answer:
2
Step-by-step explanation:
The discriminant is the quantity under the radical in the quadratic formula ...
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[tex]
When that quantity is positive, the square root is real, and the formula gives two real values for x.
Answer: x= -19/14 —> (19 over 14)
Answer:
4
Step-by-step explanation:
