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Anvisha [2.4K]
2 years ago
15

Pick a user for me (im so indecicive) most helpful answer gets brainlist ofc also lots of points, yw!

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
7 0

Answer:

I just answered the other question you asked. Why did you ask the same question twice? Also, I said the 1st one

Step-by-step explanation:

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What is 2 1/8 (Mixed number) x (times) 34 (Whole number) ?<br><br><br><br><br> PLEASE HELP ASAP
Lerok [7]

It's 289/4 or 72.25

4 0
3 years ago
Experian would like to test the hypothesis that the average credit score for an adult in Virginia is different from the average
aliya0001 [1]

Answer:

a. We fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

b. The 95% confidence interval for the true difference of means is -2.2468 and 36.2468. There is a probability of 95% that the true difference of means \mu_{1}-\mu_{2} is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

Step-by-step explanation:

Let \mu_{1}-\mu_{2} be the true difference between the average credit score for an adult in Virginia and the average credit score for an adult in North Carolina. We have the large sample sizes n_{1} = 40 and n_{2} = 35, the unbiased point estimate for \mu_{1}-\mu_{2} is \bar{x}_{1} - \bar{x}_{2}, i.e., 699-682 = 17.

The standard error is given by \sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}, i.e.,

\sqrt{\frac{(44)^{2}}{40}+\frac{(41)^{2}}{35}} = 9.8198.

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative). The rejection region is given by RR = {z | z < -1.96 or z > 1.96} where -1.96 and 1.96 are the 2.5th and 97.5th quantiles of the standard normal distribution respectively. The test statistic is Z = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{\sqrt{\frac{\sigma^{2}_{1}}{n_{1}}+\frac{\sigma^{2}_{2}}{n_{2}}}} and the observed value is z_{0} = \frac{17}{9.8198} = 1.7312. Because 1.7312 does not fall inside RR, we fail to reject the null hypothesis.

b. The endpoints for a 95% confidence interval for \mu_{1}-\mu_{2} is given by 17\pm (z_{0.05/2})9.8198, i.e., 17\pm (z_{0.025})9.8198 where z_{0.025} is the 2.5th quantile of the standard normal distribution, i.e., -1.96, so, we have 17-(1.96)(9.8198) and 17+(1.96)(9.8198), i.e., -2.2468 and 36.2468. There is a probability of 95% that the true difference of means \mu_{1}-\mu_{2} is between -2.2468 and 36.2468. This confidence interval contains the number 0, this is consistent with the results we got in a. Because we fail to reject the hypothesis that the average credit score for an adult in Virginia is different from the average credit score for an adult in North Carolina at the significance level of 0.05.

3 0
3 years ago
Respond to all of the questions within the topic (see that there are six questions below). 1. Explain how you can determine if t
Arturiano [62]

Answer:

1

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Estimate quotient using multiples, 136÷6
lana66690 [7]
136/6 = 22.6666667......
3 0
3 years ago
Read 2 more answers
Which function has the following characteristics?
iren [92.7K]

Using the asymptote concept, the function with a vertical asymptote at x = 3 and an horizontal asymptote at y = -\frac{1}{2} is given by:

f(x) = -\frac{x}{2(x - 3)}

<h3>What are the asymptotes of a function f(x)?</h3>

  • The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator.
  • The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity.

The vertical asymptote at x = 3 means that x = 3 is a root of the denominator, hence:

f(x) = \frac{g(x)}{x - 3}

The horizontal asymptote at y = -1/2 means that:

\lim_{x \rightarrow \infty} f(x) = -\frac{1}{2}

Which happens if g(x) = -\frac{x}{2}, hence the function is:

f(x) = -\frac{x}{2(x - 3)}

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

4 0
2 years ago
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