Answer:
C 9 *x^2 y^ 4 y^ 1/2
Step-by-step explanation:
(81x^4y^9)^1/2
We know that (ab)^1/2 = a^1/2 *b^1/2
(81) ^1/2 * (x^4) ^1/2 * (y^9)^1/2
We know that a^b^c = a^ (b*c)
(81) ^1/2 * (x^(4*1/2) * (y^(9*1/2)
9 *x^2 y^ 9/2
We know that y^9/2 = y^4 y^1/2
9 *x^2 y^ 4 y^ 1/2
Answer:
757.08 is your answer
Step-by-step explanation:
Hope this helped!
Sorry for not answering sooner :(
If these are terms of a geometric sequence, they have a common ratio. That is, ...
... (k -1)/(2(1 -k)) = (k +8)/(k -1)
... (k -1)² = 2(1 -k)(k +8) . . . . . multiply by the product of the denominators.
... k² -2k +1 = -2k² -14k +16 . . . eliminate parentheses
... 3k² +12k -15 = 0 . . . . . . . . put in standard form (subtract the right side)
... 3(k +5)(k -1) = 0 . . . . . . . . . factor
Possible values of k are ... -5, +1. The solution k=1 is extraneous, as it makes the first two terms 0 and the third term 8. (It doesn't work.)
The value of k is -5.
_____
The three terms are 12, -6, 3. The common ratio is -1/2.
Answer:
the intersections of these sets is 5
(3, 5pi/3) = (3cos 5pi/3, 3sin 5pi/3) = (1.5, -2.6)
