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Anastaziya [24]
3 years ago
5

Use an integer to represent a temperature of 75 degrees.

Mathematics
1 answer:
IgorC [24]3 years ago
5 0

Answer:

the answer is easy.

Step-by-step explanation:

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Evaluate the following 1340five minus 242five​
vampirchik [111]

Answer:

10980 is the correct answer

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Help!!<br><br> which expression is equivalent to (m^5 n /pq^2) ^4
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\text{Use:}\\\\\left(\dfrac{a}{b}\right)^n=\dfrac{a^n}{b^n}\\\\(a\cdot b)^n=a^n\cdot b^n\\\\(a^n)^m=a^{nm}\\\\......................................................\\\\\left(\dfrac{m^5n}{pq^2}\right)^4=\dfrac{(m^5n)^4}{(pq^2)^4}=\dfrac{(m^5)^4n^4}{p^4(q^2)^4}=\dfrac{m^{20}n^4}{p^4q^8}
8 0
3 years ago
mrs. johnson gave a sum of money to her son and daughter in the ratio 5:6. Her daughter received $2400. how muh did Mrs. Johnson
Tresset [83]
To find the total amount Mrs. Johnson gave away, you need to know how much she gave the son.  Because the ratio of the money given is 5:6, the amount of money he received has to be 5/6 of the money the daughter received.

So, the son received 5/6 of 2400.
To find this, multiply 5/6 x 2400 to get 2000.

The daughter received 2400 and the son received 2000, so the total amount Mrs. Johnson gave away is 4400 dollars.
4 0
3 years ago
(1-√-4)(-3-√-25) with steps pls
posledela

Answer:-14

Step-by-step explanation:

(1-√-4)(-3-√-25)

[(1*-3)-(1*√-25)-(√-4*-3)-(√-4*√-25)]

(-3)-(-5)-(6)-(10)

-14

5 0
3 years ago
Read 2 more answers
For a 4-unit class like Statistics, students should spend average of 12 hours studying for the class. A survey was done on 24 st
Zanzabum

Answer:

a) 68% of the students spend between 10.2 hours and 15.8 hours on Statistics each week.

b) 95% of the students spend between 7.4 hours and 18.6 hours on Statistics each week.

c) 99.7% of the students spend between 4.6 hours and 21.4 hours on Statistics each week.

Step-by-step explanation:

The Empirical Rule states that, for a normally distributed(bell-shaped) random variable:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviation of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we have that:

Mean = 13 hours

Standard deviation = 2.8 hours.

a) 68% of the students spend between hours and hours on Statistics each week.

Within 1 standard deviation of the mean.

13 - 2.8 = 10.2 hours

13 + 2.8 = 15.8 hours

68% of the students spend between 10.2 hours and 15.8 hours on Statistics each week.

b) 95% of the students spend between hours and hours on Statistics each week.

Within 2 standard deviations of the mean

13 - 2*2.8 = 7.4 hours

13 + 2*2.8 = 18.6 hours

95% of the students spend between 7.4 hours and 18.6 hours on Statistics each week.

c) 99.7% of the students spend between hours and hours on Statistics each week.

Within 3 standard deviations of the mean

13 - 3*2.8 = 4.6 hours

13 + 3*2.8 = 21.4 hours

99.7% of the students spend between 4.6 hours and 21.4 hours on Statistics each week.

8 0
3 years ago
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