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Rudik [331]
3 years ago
6

If one side of a square measures (3x − 8) ft. , find the area of the square.

Mathematics
1 answer:
aev [14]3 years ago
4 0

Answer:

The Answer Would be 9 cm2

Step-by-step explanation:

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A _________ is used to change one unit to another?
slamgirl [31]

Answer:

conversion factor

Step-by-step explanation:

A conversion factor is a number used to change one set of units to another, by multiplying or dividing. When a conversion is necessary, the appropriate conversion factor to an equal value must be used. For example, to convert inches to feet, the appropriate conversion value is 12 inches equal 1 foot.

8 0
3 years ago
Look at these numbers. 0.3,
timama [110]
0.3.......the 3 is in the tenths place 
0.103....the 3 is in the thousandths place
0.13.....the 3 is in the hundredths place

0.3 is ur answer

8 0
3 years ago
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The cover of a photo album has an area of 97.5 square inches. find its arwa in square centimeters
Anna [14]
Convert 97.5 inches to centimeters. 97.5 in=247.65 cm. The area is 247.65 inches^2. Hope this helps! ;)
4 0
3 years ago
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In the straightedge and compass construction of the parallel line below, which of the following reasons can you use to prove tha
Eva8 [605]

Answer:

D.

Step-by-step explanation:

Lines EG and CD are cut by transversal CF.

By construction, ∠FEG=∠FCD. These two angles are corresponding angles.

Since two corresponding angles are congruent, then lines EG and CD are parallel (by  converse of the corresponding angles postulate).

Converse of the Corresponding Angles Postulate: If the corresponding angles formed by two lines and a transversal are congruent, then lines are parallel.

3 0
3 years ago
D(x)=(x^2-12x+20)/(3x)
krok68 [10]

Answers:

Vertical asymptote: x = 0

Horizontal asymptote: None

Slant asymptote: (1/3)x - 4

<u>Explanation:</u>

d(x) = \frac{x^{2}-12x+20}{3x}

      = \frac{(x-2)(x - 10)}{3x}

Discontinuities: (terms that cancel out from numerator and denominator):

Nothing cancels so there are NO discontinuities.

Vertical asymptote (denominator cannot equal zero):

3x ≠ 0  

<u>÷3</u>   <u>÷3 </u>

x ≠ 0

So asymptote is to be drawn at x = 0

Horizontal asymptote (evaluate degree of numerator and denominator):

degree of numerator (2) > degree of denominator (1)

so there is NO horizontal asymptote but slant (oblique) must be calculated.

Slant (Oblique) Asymptote (divide numerator by denominator):

  •        <u>(1/3)x - 4    </u>
  •    3x)    x² - 12x + 20
  •             <u>x²        </u>
  •                  -12x
  •                  <u>-12x         </u>
  •                             20 (stop! because there is no "x")

So, slant asymptote is to be drawn at (1/3)x - 4



6 0
3 years ago
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