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Rama09 [41]
3 years ago
15

PLEASE HELP ON THESE 2 QUESTIONS

Mathematics
1 answer:
photoshop1234 [79]3 years ago
7 0
1) 9/4x-2 = 12/3x+2
9(3x+2) = 12(4x -2)
27x +18 = 48x -24
27x-27x +18 = 48x-27x -24
18 = 21x -24
18 +24 = 21x -24+24
42 = 21x
42/21 = 21x/21
x= 2

2. x/9 = 25/15

15x = 225
15x/15 = 225/15
x= 15

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Leo works at McDonalds, and gets paid $8.50 hr. He passed his store’s inspection and received a $100 bonus.
Semmy [17]

Answer:

$8.50hr+ $100=x

Step-by-step explanation:

His $8.50 per hour is given to him plus $100 bonus.

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3 years ago
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Lines a and b are parallel. What is the measure of angle s?
Arte-miy333 [17]

Answer:

Step-by-step explanation:

t = 158                         Corresponding angles

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s = 180 - 158

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As a note, all angles in this situation are either 158 or 22.

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What is the quotient of StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction? Star
Komok [63]

The quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

<h3>What is the quotient?</h3>

Quotient is the resultant number which is obtain by dividing a number with another. Let a number a is divided by number b. Then the quotient of these two number will be,

q=\dfrac{a}{b}

Here, (<em>a, b</em>) are the real numbers.

The number StartFraction 7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline EndFraction, given can be written as,

\dfrac{7^{-1}}{7^{-2}}

Let the quotient of this division is n. Therefore,

n=\dfrac{7^{-1}}{7^{-2}}

A number in numerator of a fraction with negative exponent can be written in the denominator with the same but positive exponent and vise versa. Therefore,

n=\dfrac{7^{2}}{7^{1}}\\n=7

Hence, the quotient of the number given number  7 Superscript negative 1 Baseline Over 7 Superscript negative 2 Baseline is 7.

Learn more about the quotient here;

brainly.com/question/673545

7 0
3 years ago
Which is the solution set for –7 ≤ 4x + 1 ≤ 5?<br><br> I added a picture !
Oksi-84 [34.3K]
-7\leq4x+1\leq5\ \ \ \ |subtract\ 1\\\\-7-1\leq4x+1-1\leq5-1\\\\-8\leq4x\leq4\ \ \ \ |divide\ by\ 4\\\\-8:4\leq4x:4\leq4:4\\\\\boxed{-2\leq x \leq1\Rightarrow x\in[-2;\ 1]}

\boxed{x\geq-2\ and\ x\leq1}\to\answer{\boxed{C}}
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3 years ago
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