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xenn [34]
3 years ago
14

2x+3y=12 how do I solve for x and y

Mathematics
2 answers:
Elena-2011 [213]3 years ago
4 0

2x+3y= 12

To solve for the x intercept, y=0

2x+3(0)= 12

2x= 12

Divide both sides by 2

2x/2x= 12/2x

X= 6

So:(6,0)

To solve for y intercept, x=0

2(0)+3y= 12

3y= 12

Divide both sides by 3

3y/3y= 12/3

Y= 4

So: (0,4)


GaryK [48]3 years ago
3 0
2x + 3y = 12
2x - 2x + 3y = 12 - 2x
<u>3y</u> = <u>12 - 2x</u>
 3          3
  y = 4 - 2/3x
2x + 3(4 - 2/3x) = 12
2x + 12 - 2x = 12
2x - 2x + 12 = 12
0x + 12 = 12
<u>       -12   -12</u>
        <u>0x</u> = <u>0</u>
         0     0
         x = 0
2(0) + 3y = 12
0 + 3y = 12
<u>-0          -0  </u>
      <u>3y</u> = <u>12</u>
       3      3
        y = 4
  (x, y) = (0, 4)
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