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3 years ago

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PLEASE i need answer will give brainleist answer!!!

1 answer:

Alik [6]3 years ago

7 0

The company's sales increase by $940
(0.94×1000)

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What is the inverse of the function f(x) = x +3?

MAXImum [283]

Answer:

f⁻¹(x) = x - 3

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Equality Properties

Multiplication Property of Equality
Division Property of Equality
Addition Property of Equality
Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

Functions
Function Notation
Inverse Functions

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

f(x) = x + 3

<u>Step 2: Find</u>

Swap: x = y + 3
[Subtraction Property of Equality] Isolate <em>y</em>: x - 3 = y
Rewrite: f⁻¹(x) = x - 3

6 0

3 years ago

When Andrei surveyed 36 random seventh-grade students in the lunchroom, he found that 7 out of 9 would like to try or have

Alex73 [517]

Answer:

About 630 seventh-grade students would like to snorkel

Step-by-step explanation:

if you do

7/9 x 90 equals 630/810 total students

7 0

3 years ago

Writing to Explain Suppose you have a 100-mL cup, you can a 500-mL cup. List two different ways

Misha Larkins [42]

5 100ml cups and 1 500 ml cup

and 2 500 ml cups

4 0

3 years ago

What is the midpoint of (-7,-9) (6,3)

Advocard [28]

Answer :

Let the first term of both the terms be $\: \sf \: x _1 \: \: \& \: \: x _2$ and last term be $\: \sf \: y _1 \: \: \& \: \: y_2\\$

Now, by using the mid point formula to find the mid point of the segment -

$\\ \sf \bigg( \frac{x_1 + x_2}{2} , \: \frac{y_1 + y_2}{2} \bigg) \\$

Now, by substituting the values of both x and y -

$\\ \sf \bigg( \frac{ - 7 + 6}{2} , \: \frac{ - 9 + 3}{2} \bigg) \\$

Adding -7 and 6 -

$\\ \sf \bigg( \frac{ - 1}{2} , \frac{ - 9 + 3}{2} \bigg) \\$

Now, move the negative in front of the fraction -

$\\ \sf \bigg( \frac{ - 1}{2} , \frac{ - 6}{2} \bigg) \\ \\ \\ \sf \bigg( \frac{ - 1}{2} , - 3\bigg) \\$

6 0

3 years ago

An environment engineer measures the amount ( by weight) of particulate pollution in air samples ( of a certain volume ) collect

Serggg [28]

Answer:

$k = 1$

$P(x > 3y) = \frac{2}{3}$

Step-by-step explanation:

Given

$f \left(x,y \right) = \left{ \begin{array} { l l } { k , } & { 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x } & { \text 0, { elsewhere. } } \end{array} \right.$

Solving (a):

Find k

To solve for k, we use the definition of joint probability function:

$\int\limits^a_b \int\limits^a_b {f(x,y)} \, = 1$

Where

${ 0 \leq x} \leq 2,0 \leq y \leq 1,2 y \leq x }$

Substitute values for the interval of x and y respectively

So, we have:

$\int\limits^2_{0} \int\limits^{x/2}_{0} {k\ dy\ dx} \, = 1$

Isolate k

$k \int\limits^2_{0} \int\limits^{x/2}_{0} {dy\ dx} \, = 1$

Integrate y, leave x:

$k \int\limits^2_{0} y {dx} \, [0,x/2]= 1$

Substitute 0 and x/2 for y

$k \int\limits^2_{0} (x/2 - 0) {dx} \,= 1$

$k \int\limits^2_{0} \frac{x}{2} {dx} \,= 1$

Integrate x

$k * \frac{x^2}{2*2} [0,2]= 1$

$k * \frac{x^2}{4} [0,2]= 1$

Substitute 0 and 2 for x

$k *[ \frac{2^2}{4} - \frac{0^2}{4} ]= 1$

$k *[ \frac{4}{4} - \frac{0}{4} ]= 1$

$k *[ 1-0 ]= 1$

$k *[ 1]= 1$

$k = 1$

Solving (b): $P(x > 3y)$

We have:

$f(x,y) = k$

Where $k = 1$

$f(x,y) = 1$

To find $P(x > 3y)$ , we use:

$\int\limits^a_b \int\limits^a_b {f(x,y)}$

So, we have:

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {f(x,y)} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 {1} dxdy$

$P(x > 3y) = \int\limits^2_0 \int\limits^{y/3}_0 dxdy$

Integrate x leave y

$P(x > 3y) = \int\limits^2_0 x [0,y/3]dy$

Substitute 0 and y/3 for x

$P(x > 3y) = \int\limits^2_0 [y/3 - 0]dy$

$P(x > 3y) = \int\limits^2_0 y/3\ dy$

Integrate

$P(x > 3y) = \frac{y^2}{2*3} [0,2]$

$P(x > 3y) = \frac{y^2}{6} [0,2]\\$

Substitute 0 and 2 for y

$P(x > 3y) = \frac{2^2}{6} -\frac{0^2}{6}$

$P(x > 3y) = \frac{4}{6} -\frac{0}{6}$

$P(x > 3y) = \frac{4}{6}$

$P(x > 3y) = \frac{2}{3}$

8 0

3 years ago