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Fudgin [204]
4 years ago
6

Find the domain of fg

Mathematics
2 answers:
vazorg [7]4 years ago
7 0
We have the following functions:
 f (x) = x ^ 2 + 1
 g (x) = 1 / x
 Multiplying we have:
 (f * g) (x) = (x ^ 2 + 1) * (1 / x)
 Rewriting:
 (f * g) (x) = ((x ^ 2 + 1) / x)
 Therefore, the domain of the function is given by all the values of x that do not make zero the denominator.
 We have then:
 All reals except number 0
 Answer:
 
b. all real numbers, except 0
Vesnalui [34]4 years ago
4 0

Answer:

the correct answer is B

Step-by-step explanation:

I took the test

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Find the distance between the points (-21, 17) and (33, 17)
Norma-Jean [14]
Plug it into the distance formula.

d= (sqrt) (x2-x1)^2 +(y2-y1)^2

d= (sqrt) (17-17)^2 + (33-(-21)^2
d=(sqrt) (0)^2 + (33 +21)^2
d= (sqrt) (54)^2
d= (sqrt) 2916
d=54

The distance is 54 units. 

I hope this helps!
~kaikers
7 0
3 years ago
Need help finding X​
Dvinal [7]

the value of x is 90

8 0
3 years ago
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Does the function f(x) = 2x^2− 6x + 9 have a minimum or a maximum? Identify its value.
exis [7]

Answer:

minimum value of function is   \frac{45}{8} .

Step-by-step explanation:

Given function represents a parabola.

Now, here coefficient of x^{2} is positive , so the parabola will be facing upwards and thus the function will be having a minimum.

Now, as we know that minimum value of a parabolic function occurs at

x = \frac{-b}{4a} .

Where , b represents the coefficient of x and a represents the coefficient of x^{2} .

here, a = 2 , b = -6

Thus \frac{-b}{4a} = \frac{6}{8}

                                            =  \frac{3}{4}

So, at x =  \frac{3}{4}  minimum value will occur and which equals

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4 0
3 years ago
I’m pretty sure the answer is 50.3 but could someone please tell me if it’s square yards or yards?
olchik [2.2K]

Answer:

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Step-by-step explanation:

3 0
3 years ago
A 4-foot tall person standing with her back to the sun casts an 6-foot long shadow.
e-lub [12.9K]

Answer:  \alpha=34\°

Step-by-step explanation:

1. Based on the information given in the problem, you can draw the right triangle shown in the figure attached.

2. Keeping the informationn given in the problem, you can calculate the angle that the sum makes with the ground (\alpha)as you can see below:

arctan\alpha=\frac{opposite}{adjacent}

Where:

opposite=4\\adjacent=6

3. Then:

 arctan\alpha=\frac{4}{6}

\alpha=34\°

7 0
3 years ago
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