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Fudgin [204]
3 years ago
6

Find the domain of fg

Mathematics
2 answers:
vazorg [7]3 years ago
7 0
We have the following functions:
 f (x) = x ^ 2 + 1
 g (x) = 1 / x
 Multiplying we have:
 (f * g) (x) = (x ^ 2 + 1) * (1 / x)
 Rewriting:
 (f * g) (x) = ((x ^ 2 + 1) / x)
 Therefore, the domain of the function is given by all the values of x that do not make zero the denominator.
 We have then:
 All reals except number 0
 Answer:
 
b. all real numbers, except 0
Vesnalui [34]3 years ago
4 0

Answer:

the correct answer is B

Step-by-step explanation:

I took the test

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Round your answer to the nearest hundredth.<br> с<br> B<br> 40°<br> ?<br> 7<br> А
igor_vitrenko [27]

Answer:

take 40 degree as reference angle

using sine rule

let opposite be x

sine 40=opposite/hypotenuse

0.64=x/7

0.64*7=x

4.48=x

Step-by-step explanation:

3 0
3 years ago
Pattern A follows the rule "add 5" and Pattern B follows the rule "subtract 2."
xxTIMURxx [149]

Answer:

(25,12)

Step-by-step explanation:

pattern A=20+5

=25

pattern B=14-2

=12

25,12

4 0
2 years ago
Help if you don’t mind
Fantom [35]

Answer:

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Step-by-step explanation:

5 0
3 years ago
PRECALCULUS please help​
sergejj [24]

Answer:

<h2>( f - g)(x)  =  \frac{2x -  \sqrt{x} + 14 }{3x}</h2>

Step-by-step explanation:

f(x) =  \frac{2x + 6}{3x}  \\  \\ g(x) =  \frac{ \sqrt{x}  - 8}{3x}

To find ( f - g)(x) , subtract g(x) from f(x)

That's

( f - g)(x) =  \frac{2x + 6}{3x}  -  \frac{ \sqrt{x}  - 8}{3x}

Since they have a common denominator that's 3x we can subtract them directly

That's

\frac{2x  +  6}{3x}  -  \frac{ \sqrt{x}  - 8}{3x}    =  \frac{2x  + 6 - ( \sqrt{x} - 8) }{3x}  \\  =  \frac{2x + 6 -  \sqrt{x} + 8 }{3x}  \\  =  \frac{2x -  \sqrt{x} + 6 + 8 }{3x}

We have the final answer as

<h3>( f - g)(x)  =  \frac{2x -  \sqrt{x} + 14 }{3x}</h3>

Hope this helps you

6 0
3 years ago
What property is x-7=11
SOVA2 [1]

Answer:

Cummative

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
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