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3 years ago

9

the number of students enrolled in school increase by 12% from last year to this year. The enrollment this year is 13,640. What

was the enrollment last year?

1 answer:

algol133 years ago

8 0

Use a calculator. I would walk you through it, but it should be simple.

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I honestly don’t understand this at all can you help?

blondinia [14]

A. the first box is 7
the second box is 2
the third box is 100
the fourth box is 6.5
RULE: times 3 + 2
b. the first box is 45/2
the second box is -0.75
the third box is 0
the fourth box is 2.75
RULE: times 5/2
c. the first box is 1 1/2
the second box is 6
the third box is -4
the fourth box is -1.75
RULE: times half add one

6 0

3 years ago

Read 2 more answers

Is 4 a solution of2=8

JulsSmile [24]

Answer:

Two doesn’t equal 8. Theoretically, eight is the solution...

Step-by-step explanation:

5 0

3 years ago

An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with _______ exactly one

Dafna11 [192]

Answer:

exactly one, 0's, triangular matrix, product and 1.

Step-by-step explanation:

So, let us first fill in the gap in the question below. Note that the capitalized words are the words to be filled in the gap and the ones in brackets too.

"An elementary ntimesn scaling matrix with k on the diagonal is the same as the ntimesn identity matrix with EXACTLY ONE of the (0's) replaced with some number k. This means it is TRIANGULAR MATRIX, and so its determinant is the PRODUCT of its diagonal entries. Thus, the determinant of an elementary scaling matrix with k on the diagonal is (1).

Here, one of the zeros in the identity matrix will surely be replaced by one. That is to say, the determinants = 1 × 1 × 1 => 1. Thus, it is a a triangular matrix.

3 0

3 years ago

HELP PLEASEEE I NEED HELP QUICK

madam [21]

Answer:

C) If the perfect square terms are A^2 and B^2 and other terms must be 2 AB and -2AB

Step-by-step explanation:

As,

$(a^2+2ab+b^2)=(a+b)^2\\(a^2-2ab+b^2)=(a-b)^2$

7 0

3 years ago

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Is the given point interior , exterior, or on the circle k (x+2)2 + (y-3)2 =18 P (8,4)

Mnenie [13.5K]

One way would be to find the distance from the point to the center of the circle and compare it to the radius

for
$(x-h)^2+(y-k)^2=r^2$
the center is (h,k) and the radius is r

and the distance formula is
distance between $(x_1,y_1)$ and $(x_2,y_2)$ is
$D=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}$

r=radius
D=distance form (8,4) to center

if r>D, then (8,4) is inside the circle
if r=D, then (8,4) is on the circle
if r<D, then (8,4) is outside the circle

so
$(x+2)^2+(y-3)^2=18$
$(x-(-2))^2+(y-3)^2=(\sqrt{18})^2$
$(x-(-2))^2+(y-3)^2=(3\sqrt{2})^2$

the radius is $3\sqrt{2}$
center is (-2,3)

find distance between (8,4) and (-2,3)

$D=\sqrt{(8-(-2))^2+(4-3)^2}$
$D=\sqrt{(8+2)^2+(1)^2}$
$D=\sqrt{10^2+1}$
$D=\sqrt{100+1}$
$D=\sqrt{101}$

$r=3\sqrt{2}$ ≈4.2
$D=\sqrt{101}$ ≈10.04

do r<D

(8,4) is outside the circle

6 0

4 years ago