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3 years ago

9

the number of students enrolled in school increase by 12% from last year to this year. The enrollment this year is 13,640. What

was the enrollment last year?

1 answer:

algol133 years ago

8 0

Use a calculator. I would walk you through it, but it should be simple.

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State if the two triangles are congruent. If they are, state how you know.

Mars2501 [29]

I believe that it is congruent by SAS

6 0

3 years ago

How would you describe an angle to someone who had never heard of one before? How would you describe how it is measured? Is it t

valkas [14]

An angle is where two lines intersect at a point. It is measured by the distance between the two lines in degrees. Boom. Did it without math-ey words. i'm da best

7 0

3 years ago

Which of these is equal to cos 19°?

PilotLPTM [1.2K]

Hello there.

Question: <span>Which of these is equal to cos 19°?

Answer: There aren't any options so i can only give the value for it which is 0.9455

</span>Hope This Helps You!
Good Luck Studying ^-^

4 0

3 years ago

The Mariners buy jerseys wholesale for $48 and sells for $468. What’s the markup rate?

AlekseyPX

Answer:

975%

Step-by-step explanation:

468/48 - 9.75

9.75 in percent form is 9.75*100=975%

Too much for a Mariners jersey if you ask me :D

8 0

3 years ago

3. A company with loud machinery needs to cut its sound intensity to 44% of its original level. By how many decibels would the l

sergeinik [125]

Answer: <em>3. The correct option is: A) 3.57 decibels.</em>

<em>6. The correct option is: B) $ln(\frac{x^2}{c^5})$ </em>

Step-by-step explanation:

3. Sound intensity is cut to 44% of its original level. That means, if the original sound intensity was 100, then now sound intensity will be 44.

So, $I_{0}= 100$ and $I= 44$

Using the formula $L= 10log(\frac{I}{I_{0}})$ , we will get.....

$L= 10log(\frac{44}{100})\\ \\ L= 10log(0.44)\\ \\ L= 10(-0.3565...)=-3.565...\approx -3.57$

<em>(Rounded to the nearest hundredth)</em>

So, the loudness would be reduced by 3.57 decibels.

6. Given expression is: $2ln(x) - 5ln(c)$

First applying the property $m*log(x)= log(x^m)$ , we will get.....

$ln(x^2)-ln(c^5)$

Now using the formula, $log(a)-log(b)= log(\frac{a}{b})$ , we will get....

$ln(x^2)-ln(c^5) = ln(\frac{x^2}{c^5})$

Thus, the answer as a single natural logarithm is $ln(\frac{x^2}{c^5})$

8 0

3 years ago