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3 years ago

What can go into 10.8 and 36

2 answers:

7 0

10.9
35.99999999999999999999999999999999999 (repeating)
11.1
11.12324343
23.8743894099

Basically any number between 10.8 and 36.
Hope I helped.

BlackZzzverrR [31]3 years ago

4 0

36, 54, and 108 19 hope it helps

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2 years ago

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paulette has arrived at cape horn. there are five penguins waiting to cross over to antarctica. jim goes before john but after j

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Well, this is a guess. Jim goes before john, but after joe. So Jim is second. John is third, so that leaved Joe.

Joe, Jim, John. But I don't know about the other 2.

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2 years ago

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2 years ago

PLEASE HELP..... I WILL GIVE BRAINLIEST!!

Yakvenalex [24]

For the first part:

Every shirt she grabs, will cost her dollars, so if she grabs 3 shirts, then the cost of the shirts is:

$12+12+12=3(12)$

With the same rationale, if she grabs 2 pairs of jeans, the cost of the jeans is:

$19+19=2(19)$

So, her total is:

$3(12)+2(19)$

If you subtract 3 from the total, then the expression is:

$3(12)+2(19)-3=36+38-3=71$

For the second part:

If she's paying 3 less for each shirt, then the cost of 3 shirts will become:

$(12-3)+(12-3)+(12-3)=3(12-3)$

In the same fashion, for the two jeans:

$(19-3)+(19-3)=2(19-3)$

So the expression for the total cost is:

$3(12-3)+2(19-3)=36-9+38-6=59$

For number three:

The amounts are different because the cost of the total purchase is different than the cost of each element that makes up the total purchase.

For number four:

If you're the owner, you want to give the smallest amount of discount (the one in part 1/a).

So you could clarify by saying there's 3 dollars of the TOTAL purchase's cost.

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3 years ago

a toy manufacturer has designed a new piece for use in building models. It is a cube with side lengths 7 mm and has a 3 mm in di

Ray Of Light [21]

Given that the cubical piece has side (s) 7 mm, and a cylindrical hole of diameter (d) as 3 mm.

The volume of the piece can be calculated as,

$\begin{gathered} \text{Volume of piece}=\text{ Volume of cube}-\text{ Volume of cylinder} \\ V=s^3-\frac{\pi}{4}d^2s \\ V=7^3-\frac{\pi}{4}(3)^2(7) \\ V=343-\frac{63\pi}{4} \\ V\approx293.52mm^3 \\ V\approx293.52\times10^{-9}\text{ }m^3 \end{gathered}$

It is mentioned that the material costs $207 per cubic meter, so the cost (c) of 1 piece is calculated as,

$\begin{gathered} \text{Cost of 1 piece}=\text{ Cost per unit volume}\times\text{ Volume of 1 piece} \\ c=207\times293.52\times10^{-9} \\ c\approx60758.64\times10^{-9} \end{gathered}$

This is the cost (in dollars) for 1 piece.

Given that the manufacturer wants to produce 1,000,000 such pieces, so the total cost (TC) is calculated as,

$\begin{gathered} \text{Total Cost}=\text{ Cost per piece}\times\text{ No. of pieces} \\ TC=60758.64\times10^{-9}\times1,000,000 \\ TC=60758.64\times10^{-9}\times10^6 \\ TC=60758.64\times10^{-3} \\ TC=60.75864 \\ TC\approx60.75 \end{gathered}$

Thus, the total prototypes will cost around $60.75

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1 year ago