Answer:
D. DE = 24 yd, EF = 10 yd
Step-by-step explanation:
Solve for the unknown angles by setting up common ratios and cross multiplying. You can use this method because they are similar triangles.
For example, DE can be found by setting the ratios of AC/AB equal to the ratio of DF/DE.
13/12 = 26/x
Simply solve for x!
<span>I think the height is 2/3 that of a side of the base. If that is correct, then the height is h = 2/3s.
The formula for the volume of a pyramid is \[V=\frac{ 1 }{ 3 }s ^{2}h\]
Normally it would be B for base area, but since this is a square and the height is in terms of s, that would be the formula.
If we find the area based on the fact that h = 2/3s, then it appears that the formula would be
V=1/3s^2 x 2/3s
If you multiply that all out, it would be V= 2 / 9s ^3
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Step-by-step explanation:
4x 3.5 + 4x 2.3
14 + 9.2
= 23.2
Answer:
Let p be the number of pens and let n be the number of notebooks.
4 notebooks + 3 pens cost $96 so 4n + 3p = 96
2 notebooks + 2 pens cost $54 so 2n + 2p = 54
We find n and p by solving the system of linear equations:
4n + 3p = 96
2n + 2p = 54
4n + 3p = 96
4n + 4p = 108 (we multiply this by 2 to cancel out 4n in both equations)
We then subtract the two equations:
(4n + 3p) - (4n + 4p) = 96 - 108
-p = -12
p = 12
So, a pen costs 12 dollars. We can use p to find n. We substitute 12 for p in one of our earlier equations:
2n + 2p = 54
2n + 2(12) = 54
2n + 24 = 54
2n = 30
n = 15
So, a notebook costs 15 dollars and a pen costs 12. Now, we need to find the cost of 8 notebooks and 7 pens:
8n + 7p = ?
8(15) + 7(12) = ?
120 + 84 = 204.
Thus, 8 notebooks and 7 pens cost 204 dollars (why is it so expensive lol).