Write a program whose input is two integers. Output the first integer and subsequent increments of 10 as long as the value is le
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Answer:
Following are the program to this question:
Q1:
#include <iostream> //including header file
using namespace std;
int main() //defining main method
{
int m,n,i; //defining integer variable
cout<<"Enter starting value: "; //print message
cin>>m; //input m variable value
cout<<"Enter ending value: ";//print message
cin>>n;//input n variable value
for(i=m;i<=n;i++) //defining loop to count even number
{
if(i%2==0) //check even number condition
{
cout<<i<<" "; //print value
}
}
return 0;
}
Q2:
#include<iostream> //include header file
using namespace std;
void menu() //define method menu
{
cout<<"Enter 1 for print your name and id: "<<endl; //print message
cout<<"Enter 2 for sum of odd numbers from 1 to 20: "<<endl;//print message
cout<<"Enter 3 for reverse of any number: "<<endl;//print message
cout<<"Enter 4 for exit"<<endl;//print message
}
void findsum() //define method findsum
{
int s=0,i; //defining integer variable
for(i=1;i<=20;i++) //defining loop to count odd number
{
s=s+i; //add numbers
}
cout<<"Odd number sum from 1 to 20: "<<s; //print value
}
void revers() //defining method revers
{
int n,r,rev=0; //defining integer variable
cout<<"enter any number: "; //print message
cin>>n; //input value
while(n!=0) //define loop to reverse value
{
r=n%10; //store value in r variable
rev=(rev*10)+r; //add reverse value
n=n/10; //divide digit
}
cout<<"The reverse of a given number is: "<<rev; //print reverse value
}
int main() //defining main method
{
int c,rn; //defining integer variable
char n[30]; // defining char variable
menu(); //calling menu method
cout<<"Enter your selected choice: "<<endl; //print message
cin>>c; //input value in char variable
switch(c) //defining switch
{
//defining case
case 1: cout<<"Enter your name: "<<endl; //print message for input name and id
cin>>n;//input name
cout<<"Enter registration number: "<<endl; //print message
cout<<"Name: "<<n<<endl; // print name value
cout<<"Registration number: "<<rn<<endl; // print id value
break;
case 2: findsum(); //calling findsum method
break;
case 3: revers(); //calling reverse method
break;
case 4: exit(1); // calling exit method
break;
default: cout<<"please enter valid choice"; //defining default choice
break;
}
return 0;
}
Q3:
#include <iostream>//defining header file
using namespace std;
void reverse() //defining method readInput
{
char x; //defining char variable
cout<<"Enter a character: "; //print message
cin>>x; //input value
if(x=='.') //defining condition that check value is .
return; //using return keyword
reverse(); //calling readInput method
cout<<x; //print value
}
int main() //defining main method
{
reverse(); //calling readInput method
return 0;
}
Output:
please find the attachment.
Explanation:
Description of the given question as follows:
- In question 1, three integer variable "m, n and i" is declared, in which variable "m and n" is used in user input, and variable "i" is used a loop to print even number from the user input values.
- In question 2, a menu method is declared that prints a list menus in the next line, two methods "findsum() and revers()"is declared, in which "findsum" method is used to add odd values from 1 to 20 and the revers method is used to reverse value from an input digit. In the last line main method is declared, which uses switch to call the above methods.
- In question 3, in this, a reverse method is defined, in which a char variable x is declared that input char value and define if block to check if char is equal to (.) if this is correct it will print the value in reverse order.
