Answer:
for ( initialization; condition;increment)
{
code goes here;
}
in python:
for i in list/range:
code with proper indentation
By initialization above we mean, like int i=0; etc.
By condition like i<10;
and by increment it means like i++, ++i or i+=1; etc
And in python, i can be an integer value if the range is mentioned, and it can be an item of a list if the list is used. We can also use an array, string and various other data structures in python. like we can have characters in a string and so on.
Explanation:
Please check the answer section.
The option that best explains the game is that a game can have multiple instances using the same class.
<h3>Can a class have multiple instances?</h3>
A game is one that can always create multiple instances of a class. This is known to be the reason that classes are made.
Conclusively, each object often has its own specific inner variables and they do not have only if they are static but games of multiple instances is the reason why there is only one class with the new characters.
Learn more about Games from
brainly.com/question/1786465
Answer:
An ISP is an internet service provider. AT&T and Comcast are both popular internet service providers. On the other hand, web hosts are used to host websites like att.com. The web host makes the website accessible by other people.
Explanation:
The benefits are that you don't have to worry if something breaks from like a water leake or a storm and get destroyed the home owners have to pay
The recursive function would work like this: the n-th odd number is 2n-1. With each iteration, we return the sum of 2n-1 and the sum of the first n-1 odd numbers. The break case is when we have the sum of the first odd number, which is 1, and we return 1.
int recursiveOddSum(int n) {
if(2n-1==1) return 1;
return (2n-1) + recursiveOddSum(n-1);
}
To prove the correctness of this algorithm by induction, we start from the base case as usual:
by definition of the break case, and 1 is indeed the sum of the first odd number (it is a degenerate sum of only one term).
Now we can assume that 
returns indeed the sum of the first n-1 odd numbers, and we have to proof that 
returns the sum of the first n odd numbers. By the recursive logic, we have
and by induction, is the sum of the first n-1 odd numbers, and 2n-1 is the n-th odd number. So, is the sum of the first n odd numbers, as required:
