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Vikentia [17]
3 years ago
14

Harry, Peter and 7 girls sit in a row. Harry can't sit in an end seat. In how many ways can they be arranged?

Mathematics
2 answers:
Sonja [21]3 years ago
4 0
All possibilities = 9! 
possibilities that harry sits at an end = 8! + 8! 
possibilities that harry doesn't sit at an end = 9! - 8! -8! 

vekshin13 years ago
4 0
List of all possibilities, without restrictions (ie Harry can sit in any of the 9 seats): 9!
List of all possibilities where Harry sits on either end: 2 \cdot 8!

Hence, list of all possibilities where Harry doesn't sit on either end: 9! - 2 \cdot 8! = 282,240 ways.
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Read 2 more answers
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