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3 years ago

10

Find the point-slope form of the equation of the line that passes through the given point and has the indicated slope. Point: (-

5, -3) Slope:
m = 3

1 answer:

zzz [600]3 years ago

5 0

Answer:

slope : 3

y + 3 = 3(x + 5)

y + 3 = 3x + 15

y = 3x + 12

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alex41 [277]

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Answer with explanation and steps are in the following attachment.

Step-by-step explanation:

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3 years ago

what are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotensue is 15 units long?

givi [52]

Refer to the diagram shown below.

Given:
m∠A = 19°
c = 15

By definition,
sin A = a/c
Therefore
a = c*sin A = 15*sin(19°) = 4.8835

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Answer:
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6 0

3 years ago

A city averages 14 hours of daylight in June (the longest days) and 10 in December (the shortest days). Assume that the number o

UNO [17]

The equation is given as

$y = 12 sin (6t - \pi /2) + 2$

<h3>The Amplitude </h3>

The Amplitude can be calculated as

$amplitude = \frac{max + min}{2}\\ amplitude = \frac{10+14}{2} = 12$

<h3>The Vertical Shift</h3>

The vertical shift is the average difference between the maximum and minimum.

$Vertical Shift = \frac{Max - Min}{2} = \frac{14-10}{2} = 2$

For b value

The Time Period will be twice the distance between max and min.

$time period = \frac{2\pi }{b} \\time period = 2 * distance between max and min\\b = \frac{2\pi }{2}*\frac{1}{b} = \frac{\pi }{6}$

<h3>The Period</h3>

The period is calculated as

$T = \frac{2\pi }{b} \\T = \frac{2\pi }{\frac{\pi }{b} } = 12$

The equation is given as

$y = 12 sin (6t - \pi /2) + 2$

Learn more on time period and amplitude here;

brainly.com/question/15531840

8 0

2 years ago

A skier is on the top of a 350 meter tall mountain looking down at a tree. The direct path from the tree to the skier is 505 met

denpristay [2]

Answer:

$43.87^{\circ}$

Step-by-step explanation:

We are given that

Height of mountain=350 m

Distance from the tree to the skier=505 m

We have to find the angle of depression from where the skier is standing to the base of the tree.

In triangle ABC

$\frac{AB}{AC}=sin\theta$

By using the formula

$\frac{Perpendicular\;side}{Hypotenuse}=sin\theta$

$\frac{350}{505}=sin\theta$

$sin^{-1}(\frac{350}{505})=\theta$

$\theta=43.87^{\circ}$

Hence, the angle of depression from where the skier is standing to the base of the tree= $43.87^{\circ}$

6 0

3 years ago