Are you a burger because you can be the meat in between my buns :0

and for waxz, if you buy 3 get 1 free, then you at least have to buy 3 candies 9 times, and that would be 18*9 which equals 162, which is more expensive then waxz

hope this helps!

please make me brainliest! thanks!

8 0

3 years ago

Please help me i need help points and brainly

snow_lady [41]

The values go up by 2. So your answer would be 20.

4 0

3 years ago

Read 2 more answers

when a card is drawn from a standard deck of 52 cards, what is the probability of getting a. queen b.a red. c.a queen or a red c

Brut [27]

(a) Probability of getting a queen from a deck of 52 cards = $\frac{1}{13}$

(b) Probability of getting a red card from a deck of 52 cards = $\frac{1}{2}$

(c) Probability of getting a queen or a red card from a deck of 52 cards = $\frac{7}{13}$

Solution:

Given that card is drawn from a standard deck of 52 cards.

Need to determine probability of getting

(a) queen (b) red (c) a queen or a red card

$\text { Probability of an event }=\frac{\text { favorable number of events }}{\text { total number of events }}$

(a) Calculating probability of getting a queen from a deck of 52 cards

Favorable events are getting a queen of spade, heart , diamond or club.

Means number of favorable events = 4

Total events is all possible outcomes from 52 cards

So Total number of event = 52

$\Rightarrow \text { probability of getting a queen }=\frac{4}{52}=\frac{1}{13}$

(b) Calculating probability of getting a red card from a deck of 52 cards

Number of red cards are 13 cards of diamonds and 13 cards of heart = 13+13 =26

So number of favorable event = 26

Total number of event = 52

$\Rightarrow \text { probability of getting a red card }=\frac{26}{52}=\frac{1}{2}$

(c) Calculating probability of getting a queen or red card from a deck of 52 cards

Favorable events are 26 red cards + two queens of spade and club. Need to keep in mind that queens of heart and diamond is already considered in 26 red cards.

So number of favorable event = (26+2) = 28

Total number of event = 52

$\text { Probability of getting a queen or red card }=\frac{28}{52}=\frac{7}{13}$

Summarizing the result :

(a) Probability of getting a queen from a deck of 52 cards = $\frac{1}{13}$

(b) Probability of getting a red card from a deck of 52 cards = $\frac{1}{2}$

(c) Probability of getting a queen or a red card from a deck of 52 cards = $\frac{7}{13}$

7 0

4 years ago